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Rzqust [24]
3 years ago
6

Bo buys a 3 pound bag of trail mix for a hike.He wants to make one-ounce bags for his friends with whom he is hiking.How many on

e-ounce bags can he make?
Mathematics
1 answer:
Lesechka [4]3 years ago
8 0

Answer:

He can made 48 bags of 1 ounce trail mix from 3 pounds of trail mix.

Step-by-step explanation:

Mass of trail mix Bo has = 3 pounds

1 pound = 16 ounce

3 pounds = 3\times 16 ounces = 48 ounces

Number of 1 ounce bags of trail that can be made from 48 ounces of bag be x.

x=\frac{48 ounce}{1 ounce}=48

He can made 48 bags of 1 ounce trail mix from 3 pounds of trail mix.

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In this exercise, we show that the orthogonal distance d from the plane p with equation
kodGreya [7K]
Use the cross product to find the orthogonal vector, solve the parametric equation to see at which (t) the point + orthogonal vector intersects the plane, the distance is (t) * norm of vector
3 0
2 years ago
DF bisects EDG Find FG. The diagram is not to scale.<br><br>A.15<br>B.14<br>C.19<br>D. 28​
Ahat [919]

Answer:

○ b. 14

Step-by-step explanation:

Since <em>DF</em><em> </em>is a segment bisector, set both expressions equal to each other:

3n - 4 = n + 8

-3n - 3n

__________

−4 = −2n + 8

-8 - 8

_________

−12 = −2n

__ ___

−2 −2

6 = n [Plug this back into both expressions above to get the value of 14]; 14 = FG; 14 = EF

I am joyous to assist you anytime.

6 0
3 years ago
Calculate the distance between the points Q = (2, -1) and K = (6,-9) in the coordinate plane.
White raven [17]

Answer:

Sqrt 80 = 8.94

Step-by-step explanation:

d = sqrt[(x-x)^2 + (y-y)^2]

d = sqrt [(6-2)^2 + (-9 - - 1)^2]

d = sqrt [(4)^2 + (-8)^2]

d = sqrt (16 + 64)

d = sqrt 80

d = 4 sqrt 5 = 8.94

3 0
2 years ago
What is the equation of the line that passes through the points (-1, 3) and (1, 11)
lina2011 [118]

Answer: To find the slope of this line, you would use the fomula

y2 - y1/ x2 - x1

11 - 3 / 1 - (-1)=

8/2

4

The slope of your line would be 4

3 0
3 years ago
Texas University Quarterback, Michael Daniels, is standing on his own 10-yard line. He throws a pass tword the opposite goal lin
dimulka [17.4K]

Answer: The function is y=-\frac{28}{625}(x-35)^2+30.

Explanation:

It is given that Michael Daniels, is standing on his own 10-yard line. He throws a pass toward the opposite goal line. The football is 2 yards above the ground when the quarterback lets it go.

It follows a parabolic path. Reaching its highest point, 30 yards above the ground. It is caught 50 yards downfield at a point 2 yards above the ground.

So, the initial point is (10,2) and the other point is (60,2).

The height function of a football represents a downward parabola. The maximum point of the function is called vertex. So the vertex is (h,30).

The two point (10,2) and (60,2) have same y-coordinate, therefore the function is maximum at the midpoint of both points.

midpoint=(\frac{10+60}{2}, \frac{2+2}{2})=(35,2)

So, the function is maximum at x=35. Hence the vertex is (35,30)

The standard form of the parabola is,

y=a(x-h)^2+k

Where (h,k) is vertex and a is scale factor.

Since vertex is (35,30).

y=a(x-35)^2+30

The initial point is (10,2).

2=a(10-35)^2+30

-28=625a

a=-\frac{28}{625}

So the function of height is.

y=-\frac{28}{625}(x-35)^2+30

The graph of the function is shown below.

3 0
2 years ago
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