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Harlamova29_29 [7]
3 years ago
8

Subtract: (4x5 + 8x5 + 3x) from (3x2 + 6x2 + 9x)

Mathematics
2 answers:
aniked [119]3 years ago
8 0

<u>Answer:</u>

\sf  9x^2   - 12x^5 +6x

<u>solving steps:</u>

\hookrightarrow \sf (3x^2 + 6x^2 + 9x )- (4x^5 + 8x^5 + 3x)

remove parenthesis

\hookrightarrow \sf 3x^2 + 6x^2 + 9x - 4x^5 - 8x^5 - 3x

group variables

\hookrightarrow \sf 3x^2 + 6x^2  - 4x^5 - 8x^5 - 3x+ 9x

simplify

\hookrightarrow \sf 9x^2   - 12x^5 +6x

xxMikexx [17]3 years ago
3 0

Answer:

12x^5-9x^2-6x

Step-by-step explanation:

\left(4x^5+8x^5+3x\right)-\left(3x^2+6x^2+9x\right)

4x^5+8x^5+3x-\left(3x^2+6x^2+9x\right)

(4x^5+8x^5):12x^5 ( Combine like terms)

12x^5+3x-\left(3x^2+6x^2+9x\right) (Apply the distributive law)

12x^5+3x-9x^2-9x

(3x-9x):-6x  ( Combine like terms)

12x^5-9x^2-6x

~

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