The area of a trapezoid is
A = (1/2) h (b1 + b2)
where
h is the height
b1 is length of base 1
b2 is the length of base 2
We are given with the area and assuming that the trapezoid is isosceles, the length of base 1 is
b1 = 4 ft
If the height of the trapezoid is 4.5 feet, it ensures that the shed will fit inside the trapezoid patch of land. Therefore, the height of the trapezoid is 4.5 feet.
(In the picture, QRST looks like a rhombus, so I will assume that it is a rhombus.)
In a rhombus, opposite angles are congruent based on the alternate interior angle theorem. In other words, R and T along with Q and S are both alternate interior angle pairs.
(You can actually test this by printing out a rhombus, cutting out the angles, and matching up the opposite ones.)
We know that Q is equal to 4x + 10, but we need to solve for x. Since Q and S are congruent, we can set them equal to each other:
1) 4x + 10 = 5x - 3
2) 4x + 13 = 5x
3) 5x = 4x + 13
4) x = 13
Now let's plug 13 in for Q:
5) 4(13) + 10 = 52+10 = 62
I got m<Q = 62 degrees. Hope this helps!
48/4 is 24 so you’ll need 28 1/4’s
Subtract 52 from -56 and divide by 3
Answer:
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Step-by-step explanation:
