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3 years ago

Subtract: (4x5 + 8x5 + 3x) from (3x2 + 6x2 + 9x)

Mathematics

2 answers:

aniked [119]3 years ago

8 0

<u>Answer:</u>

$\sf 9x^2 - 12x^5 +6x$

<u>solving steps:</u>

$\hookrightarrow \sf (3x^2 + 6x^2 + 9x )- (4x^5 + 8x^5 + 3x)$

remove parenthesis

$\hookrightarrow \sf 3x^2 + 6x^2 + 9x - 4x^5 - 8x^5 - 3x$

group variables

$\hookrightarrow \sf 3x^2 + 6x^2 - 4x^5 - 8x^5 - 3x+ 9x$

simplify

$\hookrightarrow \sf 9x^2 - 12x^5 +6x$

xxMikexx [17]3 years ago

3 0

Answer:

$12x^5-9x^2-6x$

Step-by-step explanation:

$\left(4x^5+8x^5+3x\right)-\left(3x^2+6x^2+9x\right)$

$4x^5+8x^5+3x-\left(3x^2+6x^2+9x\right)$

$(4x^5+8x^5):12x^5$ ( Combine like terms)

$12x^5+3x-\left(3x^2+6x^2+9x\right)$ (Apply the distributive law)

$12x^5+3x-9x^2-9x$

$(3x-9x):-6x$ ( Combine like terms)

$12x^5-9x^2-6x$

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