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Strike441 [17]
2 years ago
15

Use the following cell phone airport data speeds​ (Mbps) from a particular network. Find Q3.

Mathematics
1 answer:
d1i1m1o1n [39]2 years ago
6 0

Answer no entiendo estas cosas supongo que 0.3

Step-by-step explanation:

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Read 2 more answers
According to a polling​ organization, 24% of adults in a large region consider themselves to be liberal. A survey asked 200 resp
Varvara68 [4.7K]

Answer:

z=\frac{0.375 -0.24}{\sqrt{\frac{0.24(1-0.24)}{200}}}=4.47  

Now we can calculate the p value based on the alternative hypothesis with this probability:

p_v =P(z>4.47)=0.00000391  

The p value is very low compared to the significance level of \alpha=0.05 then we can reject the null hypothesis and we can conclude that the true proportion of people liberal is higher than 0.24

Step-by-step explanation:

Information given

n=200 represent the random sample taken

X=75 represent the number of people Liberal

\hat p=\frac{75}{200}=0.375 estimated proportion of people liberal

p_o=0.24 is the value that we want to test

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to verify if the true proportion of adults liberal is higher than 0.24:

Null hypothesis:p \leq 0.24  

Alternative hypothesis:p > 0.24  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info given we got:

z=\frac{0.375 -0.24}{\sqrt{\frac{0.24(1-0.24)}{200}}}=4.47  

Now we can calculate the p value based on the alternative hypothesis with this probability:

p_v =P(z>4.47)=0.00000391  

The p value is very low compared to the significance level of \alpha=0.05 then we can reject the null hypothesis and we can conclude that the true proportion of people liberal is higher than 0.24

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3 years ago
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