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2 years ago

Write and expression for the senqence of operations described below.

1 answer:

3 0

Raise $6$ to the second power, $6^{2}$ , the subtract r from the result, that should be $6^{2} - r$ , since we are not to simplify the expression, that's the answer.

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Find the slope and initial value of the graph below. Then write the equation of the line. Write the equation of the line.

LenaWriter [7]

Answer:

y= x + 2

Hope this helps.

7 0

3 years ago

Suzie paid a total of $324 dollar sign, 324 for x tickets to a rock festival.

MA_775_DIABLO [31]

Find the ticket unit cost: divide the total paid, $324, by the number of tickets, x. Then the form of the unit cost is

$324

--------- .

This question is highly unusual in that you write "x" as the number of tickets sold, instead of a specific number of tickets. Supposing that you'd sold 100 tickets for $324, then the unit cost would be, much more typically, a numeric ratio:

$324

----------------- = $3.24/ticket

100 tickets

6 0

4 years ago

Read 2 more answers

Cube root of b to the 12 power

kvv77 [185]

$\sqrt[3]{b^{12}}=\sqrt[3]{(b^4)^3}=b^4$

6 0

3 years ago

Anyone knows how to do questions 7 and 8? 15 pts!!

Oksi-84 [34.3K]

7) Certainly there is a typo in the statement, just see that the expression of item (ii) is different from that of item (i). Probably the correct expression is: $2x^2-4x+5$ . With this consideration, we can continue.

(i) Let E the expression that we are analyzing:

$E=2x^2-4x+5\\\\ E=2x^2-4x+2-2+5\\\\ E=2(x^2-2x+1)-2+5\\\\ E=2(x-1)^2+3$

Since (x-1)² is a perfect square, it is a positive number. So, E is a result of a sum of two positive numbers, 2(x-1)² and 3. Hence, E is a positive number, too.

(ii) Manipulating the expression:

$2x^2+5=4x\\\\ 2x^2-4x+5=0$

So, it's the case when E=0. However, E is always a positive number. Then, there is no real number x that satisfies the expression.

8) Let E the expression that we want to calculate:

$E=(2+1)(2^2+1)(2^4+1)\cdot ...\cdot(2^{32}+1)+1\\\\ E-1=(2+1)(2^2+1)(2^4+1)\cdot ...\cdot(2^{32}+1)$

Multiplying by (2-1) in the both sides:

$(2-1)(E-1)=(2-1)(2+1)(2^2+1)(2^4+1)\cdot ...\cdot(2^{32}+1)\\\\ (E-1)=\underbrace{(2-1)(2+1)}_{2^2-1}(2^2+1)(2^4+1)\cdot ...\cdot(2^{32}+1)\\\\ (E-1)=\underbrace{(2^2-1)(2^2+1)}_{2^4-1}(2^4+1)\cdot ...\cdot(2^{32}+1)\\\\ ...$ Repeating the process, we obtain: $...\\\\ E-1=(2^{32}-1)(2^{32}+1)\\\\ E-1=2^{64}-1\\\\ \boxed{E=2^{64}}$

3 0

4 years ago

Read 2 more answers

Please answer this is only algebra 1

Alexeev081 [22]

The numeric values for the given functions are as follows:

f(1/3) = 1/9.

g(4) = 8.

g(-3) = -6.

<h3>How to find the numeric value of a function or of an expression at a given point?</h3>

To find the numeric value of a function at x = a, we replace each instance of the variable, usually x, in the function by the desired value of a.

Function f(x) is defined by:

f(x) = x².

For the numeric value at x = 1/3, we replace the lone instance of x by 1/3, hence:

f(1/3) = (1/3)² = 1/9.

Function g(x) is defined by:

g(x) = 2x.

For the numeric value at x = 4, we replace the lone instance of x by 4, hence:

g(4) = 2(4) = 8.

For the numeric value at x = -3, we replace the lone instance of x by -3, hence:

g(-3) = 2(-3) = -6.

More can be learned about the numeric values of a function at brainly.com/question/28367050

#SPJ1

6 0

1 year ago