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3 years ago

8

You are given the numbers {32+n,n/8,n+225}. Find the smallest value of n so that all of the numbers in the set are natural numbe

rs.

1 answer:

gogolik [260]3 years ago

6 0

N=0,8,16,24,...; because when n=8k $(k\in \mathbb{N})$ then n/8 is natural number.
So the smallest value of n is 0.

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<u>Spanish/Espanól</u>

Respuesta:

$\frac{15}{x^5}$

Explicación paso a paso:

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