Answer:
Follows are the solution to the given point:
Step-by-step explanation:
In point a:
¬∃y∃xP (x, y)
∀x∀y(>P(x,y))
In point b:
¬∀x∃yP (x, y)
∃x∀y ¬P(x,y)
In point c:
¬∃y(Q(y) ∧ ∀x¬R(x, y)) ∀y(> Q(y) V ∀ ¬ (¬R(x,y)))
∀y(¬Q(Y)) V ∃xR(x,y) )
In point d:
¬∃y(∃xR(x, y) ∨ ∀xS(x, y))
∀y(∀x>R(x,y)) ∃x>s(x,y))
In point e:
¬∃y(∀x∃zT (x, y, z) ∨ ∃x∀zU (x, y, z))
∀y(∃x ∀z)>T(x,y,z) ∀x ∃z> V (x,y,z))
Answer:
Step-by-step explanation:
If we approximate the binomial distribution with a normal distribution, we have to apply a correction factor for the fact that we are now dealing with a continuous variable instead of a discrete one, as it was with the binomial distribution.
The probability of no more than 35 defective CDs: P(X<35)
In this case, as X=35 is not included in the interval, we start the interval from X=35-0.5=34.5.
being Pb the probability under the binomial distribution and Pn the probability under the normal distribution.
The area for the normal distribution is the one below X=34 (or P(X<34)).
Answer:
9
Step-by-step explanation:
perfect square sholud be
so (w+3)*(w+3) is perfect square and extention of it is =>w*w+6w+9