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1 year ago

Need help plzzzzz need it

Mathematics

1 answer:

Deffense [45]1 year ago

8 0

Answer:

Step-by-step explanation:

<u>From the graph we can get the intercepts:</u>

The y-intercept (0, - 1)
The x-intercept (4, 0)

<u>The rate of change (slope) is:</u>

m = (0 - (-1)) / 4 = 1/4

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2 years ago

A line includes the points (-39,49) and (0,0). What is its equation in slope-intercept form?

malfutka [58]

Answer:

The equation in the slope-intercept form will be:

$y=-\frac{49}{39}x+0$

Step-by-step explanation:

Given the points

(-39,49)

(0,0)

Finding the slope between the points using the formula

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-39,\:49\right),\:\left(x_2,\:y_2\right)=\left(0,\:0\right)$

$m=\frac{0-49}{0-\left(-39\right)}$

$m=-\frac{49}{39}$

We know that the point-slope of the line equation is

$y-y_1=m\left(x-x_1\right)$

substituting $m=-\frac{49}{39}$ and (-39,49) in the equation

$y-y_1=m\left(x-x_1\right)$

$y-49=\frac{-49}{39}\left(x-\left(-39\right)\right)$

Now writing the equation in slope-intercept form

$y=mx+b$

where m is the slope and b is the y-intercept

$y-49=\frac{-49}{39}\left(x-\left(-39\right)\right)$

$y-49=\frac{-49}{39}\left(x+39\right)$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$y-49=-\frac{49}{39}\left(x+39\right)$

$\mathrm{Add\:}49\mathrm{\:to\:both\:sides}$

$y-49+49=-\frac{49}{39}\left(x+39\right)+49$

$y=-\frac{49}{39}x+0$ ∵ $y=mx+b$

Where

$m=-\frac{49}{39}$ and the y-intercept i.e. $b=0$

Therefore, the equation in the slope-intercept form will be:

$y=-\frac{49}{39}x+0$

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3 years ago

Decrease £1280 by 60%

klemol [59]

Hi rainy here !!! so lets see lets set up your problem like this

X/1280 = 60%/100 so lets cross multiply

100 times X =100X

60 times 1280 = 76800

100X=76800 now lets divide each side by 100

100 divided by 100 = 0

76800 divided by 100 = 768

X=768

So now we have to subtract to get the total amount so 1280 minus 768 = 512

512 is your answer :)

Hope I helped if u have any questions on how I did your problem feel free to message me or comment on my page bye !!!

Love ~Rainy~

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3 years ago