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mars1129 [50]
3 years ago
14

Solve for h.........

Mathematics
1 answer:
Musya8 [376]3 years ago
8 0

Answer:

C

Step-by-step explanation:

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Factor the expression. 6x^2 + 5x + 1
Whitepunk [10]

Answer:

Option C

Step-by-step explanation:

6x² +5x + 1

6x² + 3x + 2x + 1

3x(2x + 1) + 1(2x + 1)

(3x + 1)(2x + 1)

6 0
3 years ago
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Issac lost five coins that equal $1.10. He had three types of coins. What coins did he lose?
m_a_m_a [10]

Answer:

20

Step-by-step explanation:

3 0
3 years ago
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Determine m∠1 in the triangle. 1.
AlexFokin [52]

Answer:

what is the question

Step-by-step explanation:

8 0
3 years ago
You have a goal of saving to build up a nest egg of $625,357.24, and you are going to make regular deposits to an account that p
Delvig [45]

The monthly deposit required to save up to $625,357.24 (future value) in 40 years at a 7.2% APR is <u>$225.20</u>.

<h3>What is the monthly deposit?</h3>

The monthly deposits are the periodic savings that the investor must make to achieve future value.

The monthly deposit is compounded at the monthly annual percentage rate (APR).

We can compute the required monthly deposits using an online finance calculator as follows:

N (# of periods) = 480 months (40 years x 12)

I/Y (Interest per year) = 7.2%

PV (Present Value) = $0

FV (Future Value) = $625,357.24

<u>Results</u>:

Monthly Deposits (PMT) = $225.20

Sum of all periodic payments = $108,096 ($225.20 x 480)

Total Interest = $517,261.24

Thus, to save $625,357.24 in 40 years, you need to deposit <u>$225.20</u> monthly.

Learn more about periodic deposits (payments) at brainly.com/question/13031679

#SPJ1

6 0
1 year ago
At noon, ship A is 130 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is
Hitman42 [59]

Answer:

answer = 12.87 km/h

Step-by-step explanation:

Given

Ship A is sailing east at 25 km/h = \frac{dx}{dt}

ship B is sailing north at 20 km/h =\frac{dy}{dt}

here x and y are the  sailing at t = 4 : 00 pm for ship A and B respectively

so we get x = 4 ×25 =100 km/h

                 y = 4× 20 = 80 km/h

let z is the distance between the ships, we need to find \frac{dz}{dt} at t = 4 hr

At noon, ship A is 130 km west of ship B (12:00 pm)

so equation will be

z^2 = (130-x)^2 + y^2......................(i)\\put x = 100 and y = 80 \\\\we |  | get \\

z^2 = 30^2 + 80^2\\z =\sqrt{7300} km/h

derivative first equation w . r. to t we get

2z\frac{dz}{dt} =-2(130-x)\frac{dx}{dt}+2y\frac{dy}{dt}

\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]

\frac{dz}{dt} = \frac{( -20\times25 + 80\times20)}{\sqrt{7300} }

     = \frac{1100}{85.44}\\  = 12.87km/h

8 0
3 years ago
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