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mars1129 [50]
3 years ago
14

Solve for h.........

Mathematics
1 answer:
Musya8 [376]3 years ago
8 0

Answer:

C

Step-by-step explanation:

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Im currently in the middle of taking the test :(
Ber [7]

Answer:

So..how was the test?

Step-by-step explanation:

Did you pass???

7 0
3 years ago
Help I am very bad at math I need answers by tomorrow if you can help please do​
d1i1m1o1n [39]

Answer:

Step-by-step explanation:

(a - b)(a +b) = a² - b²

1 - Sin² A = Cos² A

LHS = \frac{1}{1- Sin A} + \frac{1}{1 + Sin A}\\\\= \frac{1*(1 + Sin A)}{(1- Sin A)(1 + Sin A)} + \frac{1*(1- Sin A)}{(1 + Sin A)(1- Sin A)}\\\\= \frac{1 + Sin A+ 1 - Sin A}{1^{2}-  Sin^{2} A}\\\\= \frac{2}{1 - Sin^{2} A}\\\\= \frac{2}{Cos^{2} A}\\\\= 2 Sec^{2} A

2)  Sec² A - Tan² A = 1

LHS = \frac{1}{Sec A - Tan A}\\\\=\frac{1*(Sec A + Tan A)}{(Sec A -  Tan A)(Sec A + Tan A)}\\\\=\frac{Sec A + Tan A}{Sec^{2} A - Tan^{2} A}\\\\=\frac{Sec A + Tan A }{1}\\\\= Sec A + Tan A = RHS\\\\\\

3) LHS  = Cosec² A + Cot² A

             = Cosec² A +  Cosec² A - 1

            = 2Cosec² A - 1   = RHS

4) LHS = \frac{Sec A}{Cos A}- \frac{Tan A}{Cot A}\\\\          = Sec A*\frac{1}{Cos A}-Tan A*\frac{1}{Cot A}\\\\ = Sec A * Sec A - Tan A * Tan A\\\\= Sec^{2} A - Tan^{2} A \\\\= 1

3 0
3 years ago
If g(x)=4x-6 then g^-1(x)=?<br> (1) -4x+6<br> (2)-1/4x+1/6<br> (3)1/4x+3/2<br> (4)1/4x+6
kati45 [8]

Given:

g(x)=4x-6

To find:

The function g^{-1}(x).

Solution:

we have,

g(x)=4x-6

Put g(x)=y.

y=4x-6

Interchange x and y.

x=4y-6

Isolate y.

x+6=4y

\dfrac{x+6}{4}=y

y=\dfrac{x+6}{4}

Substitute y=g^{-1}(x).

g^{-1}(x)=\dfrac{x+6}{4}

g^{-1}(x)=\dfrac{x}{4}+\dfrac{6}{4}

g^{-1}(x)=\dfrac{x}{4}+\dfrac{3}{2}

Therefore, the correct option is (3).

4 0
3 years ago
Read 2 more answers
Write the equation of the line that is parallel to the graph of y=-4x -9, and whose y-intercept is 3.
Olin [163]

Answer:

y = -4x +3

Step-by-step explanation:

the only thing you need from the equation is the slope, which is -4

y = -4x +3

3 0
3 years ago
What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (2,
zhannawk [14.2K]

The equation of the line in point-slope form is: C. y − 5 = −(x − 2).

<h3>What is the Point-Slope Equation of a Line?</h3>

A line with a slope (m) and a point (a, b) is represented in point-slope form as, y - b = m(x - a).

Slopes of perpendicular lines are negative reciprocals of each other. Find the slope of the line in the graph given as follows:

Slope (m) = rise/run = 3 units/3 units = 1

Negative reciprocal of 1 is -1.

The slope of the line would be m = -1.

Substitute m = -1 and (a, b) = (2, 5) into y - b = m(x - a) to wrote the equation:

y - 5 = -1(x - 2)

y − 5 = −(x − 2)

Learn more about point-slope form on:

brainly.com/question/24907633

#SPJ1

5 0
2 years ago
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