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mr Goodwill [35]
2 years ago
5

Factor. ​9x^2+42xy+49y^2​ Enter your answer in the box

Mathematics
1 answer:
Sonbull [250]2 years ago
6 0

\qquad \qquad\huge \underline{\boxed{\sf ᴀɴsweʀ}}

The factorized form of the given equation is ~

\boxed{ \sf(3x + 7y) {}^{2} }

Let's solve ~

\qquad \sf  \dashrightarrow \: 9 {x}^{2}  + 42xy + 49 {y}^{2}

\qquad \sf  \dashrightarrow \: (3x) {}^{2}  + 2(3x  \times 7y) + (7y) {}^{2}

Now, as we can see, an Identity is applied here ~

that is ;

\qquad \sf  \dashrightarrow \:  {a}^{2} + 2ab +  {b }^{2}   = (a + b) {}^{2}

So, let's use this identity in our next step, taking :

  • a = 3x

  • b = 7y

\qquad \sf  \dashrightarrow \: (3x + 7y) {}^{2}

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For a party ceonma also made fruit punch with 1 gallon of orange juice, 2 quarts of grape juice, 5 pints pf pinneapple juice and
Serhud [2]

Answer:

12 cups of cranberry juice, 1 quart of grape juice, 5 pints of pineapple juice, and 1 gallon of orange juice.

Step-by-step explanation:

12 cups is the least measurement. There are 2 pints in 1 quart, so 5 pints>1 quart. A gallon has 8 pints, so it has the greatest amount.

5 0
3 years ago
How do you find the answer?
zlopas [31]
It is one because it is a simplified answer because 9*2= 18 but they got a 9 so that means they dived by 2 so 8*1=8/2=4 so the missing number is 1
3 0
4 years ago
Read 2 more answers
At one point the average price of regular unleaded gasoline was ​$3.39 per gallon. Assume that the standard deviation price per
irinina [24]

This question was not written completely

Complete Question

At one point the average price of regular unleaded gasoline was ​$3.39 per gallon. Assume that the standard deviation price per gallon is ​$0.07 per gallon and use​ Chebyshev's inequality to answer the following.

​(a) What percentage of gasoline stations had prices within 3 standard deviations of the​ mean?

​(b) What percentage of gasoline stations had prices within 2.5 standard deviations of the​ mean? What are the gasoline prices that are within 2.5 standard deviations of the​ mean?

​(c) What is the minimum percentage of gasoline stations that had prices between ​$3.11 and ​$3.67​?

Answer:

a) 88.89% lies with 3 standard deviations of the mean

b) i) 84% lies within 2.5 standard deviations of the mean

ii) the gasoline prices that are within 2.5 standard deviations of the​ mean is $3.215 and $3.565

c) 93.75%

Step-by-step explanation:

Chebyshev's theorem is shown below.

1) Chebyshev's theorem states for any k > 1, at least 1-1/k² of the data lies within k standard deviations of the mean.

As stated, the value of k must be greater than 1.

2) At least 75% or 3/4 of the data for a set of numbers lies within 2 standard deviations of the mean. The number could be greater.μ - 2σ and μ + 2σ.

3) At least 88.89% or 8/9 of a data set lies within 3 standard deviations of the mean.μ - 3σ and μ + 3σ.

4) At least 93.75% of a data set lies within 4 standard deviations of the mean.μ - 4σ and μ + 4σ.

​

(a) What percentage of gasoline stations had prices within 3 standard deviations of the​ mean?

We solve using the first rule of the theorem

1) Chebyshev's theorem states for any k > 1, at least 1-1/k² of the data lies within k standard deviations of the mean.

As stated, the value of k must be greater than 1.

Hence, k = 3

1 - 1/k²

= 1 - 1/3²

= 1 - 1/9

= 9 - 1/ 9

= 8/9

Therefore, the percentage of gasoline stations had prices within 3 standard deviations of the​ mean is 88.89%

​(b) What percentage of gasoline stations had prices within 2.5 standard deviations of the​ mean?

We solve using the first rule of the theorem

1) Chebyshev's theorem states for any k > 1, at least 1-1/k² of the data lies within k standard deviations of the mean.

As stated, the value of k must be greater than 1.

Hence, k = 3

1 - 1/k²

= 1 - 1/2.5²

= 1 - 1/6.25

= 6.25 - 1/ 6.25

= 5.25/6.25

We convert to percentage

= 5.25/6.25 × 100%

= 0.84 × 100%

= 84 %

Therefore, the percentage of gasoline stations had prices within 2.5 standard deviations of the​ mean is 84%

What are the gasoline prices that are within 2.5 standard deviations of the​ mean?

We have from the question, the mean =$3.39

Standard deviation = 0.07

μ - 2.5σ

$3.39 - 2.5 × 0.07

= $3.215

μ + 2.5σ

$3.39 + 2.5 × 0.07

= $3.565

Therefore, the gasoline prices that are within 2.5 standard deviations of the​ mean is $3.215 and $3.565

​(c) What is the minimum percentage of gasoline stations that had prices between ​$3.11 and ​$3.67​?

the mean =$3.39

Standard deviation = 0.07

Applying the 2nd rule

2) At least 75% or 3/4 of the data for a set of numbers lies within 2 standard deviations of the mean. The number could be greater.μ - 2σ and μ + 2σ.

the mean =$3.39

Standard deviation = 0.07

μ - 2σ and μ + 2σ.

$3.39 - 2 × 0.07 = $3.25

$3.39 + 2× 0.07 = $3.53

Applying the third rule

3) At least 88.89% or 8/9 of a data set lies within 3 standard deviations of the mean.μ - 3σ and μ + 3σ.

$3.39 - 3 × 0.07 = $3.18

$3.39 + 3 × 0.07 = $3.6

Applying the 4th rule

4) At least 93.75% of a data set lies within 4 standard deviations of the mean.μ - 4σ and μ + 4σ.

$3.39 - 4 × 0.07 = $3.11

$3.39 + 4 × 0.07 = $3.67

Therefore, from the above calculation we can see that the minimum percentage of gasoline stations that had prices between ​$3.11 and ​$3.67​ corresponds to at least 93.75% of a data set because it lies within 4 standard deviations of the mean.

4 0
4 years ago
Please help solve this
neonofarm [45]
F(x)= (x+13)(x-2) in expanded form, it would be x^2+11x-26
5 0
3 years ago
Hi can someone help me with this I will thank u so much and give u stars and a thank u
AnnZ [28]

Answer:

i think it is .64

Step-by-step explanation:

4 0
3 years ago
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