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Flura [38]
2 years ago
10

I’ll give brainliest to whomever helps.

Mathematics
1 answer:
Kobotan [32]2 years ago
5 0

Answer:

2x²-60x+84500

Step-by-step explanation:

=(x-190)^{2} +(x+220)^{2}\\\\=x^{2} -2*x*190+190^{2} +x^{2} +2*x*220+220^{2} \\\\=x^{2} +x^{2} -380x+440x+36100+48400\\\\=2x^{2} -60x+84500

I think this must be the answer.

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Could someone please help answer this, thank you, will give brainliest, plz no spam (home work help) thanks!
kolezko [41]
A < -12

1/3a < -4
a < -12


Mark brainliest please
5 0
3 years ago
Read 2 more answers
7 + r ≥ 18<br> Which is true?<br> 11<br> 10<br> 9
sdas [7]

Answer:

11

Step-by-step explanation:

ez

3 0
2 years ago
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What are the coordinates of the hole in the graph of the function f(x) ?
Vinvika [58]
ANSWER

(3, \infty )

EXPLANATION

The given function is

f(x) = \frac{ {x}^{2} - 9}{x - 3}

When we plug in x=3 into this function, we obtain,

f(3) = \frac{0}{0}

This means that the function is discontinuous at x=3.

We need to simplify the function to obtain,

f(x) = \frac{(x - 3)(x + 3)}{(x - 3)}

This implies that,

f(x) = x + 3

The graph this function is a straight line that is continuous everywhere.

To graph

f(x) = \frac{ {x}^{2} - 9}{x - 3}
we draw the graph of

f(x) = x + 3
and leave a hole at x=3.

See diagram in attachment.

Hence the coordinates of hole is

(3, \infty )

6 0
3 years ago
Match these items match the items in the left column to the items in the right column
Setler [38]
1) Base
2) Exponent
3) Metric system
5 0
3 years ago
Can someone help and give me a step by step explanation please?!
vitfil [10]

9514 1404 393

Answer:

  • ∠QSR = 78°
  • ∠SQR = 51°

Step-by-step explanation:

The measure of an inscribed angle (QTR) is half the measure of the arc it intercepts. The measure of an arc is the same as the measure of the central angle it intercepts. So, we have ...

  ∠QSR = 2×∠QTR

  ∠QSR = 2×39°

  ∠QSR = 78°

__

Sides SQ and SR are radii of circle S, so are the same length. That means triangle QRS is an isosceles triangle and the base angles SQR and SRQ are congruent. The sum of angles in a triangle is 180°, so we have ...

  ∠QSR + 2(∠SQR) = 180°

  78° + 2(∠SQR) = 180° . . . . fill in the value we know

  2(∠SQR) = 102° . . . . . . . . . subtract 78°

  ∠SQR = 51° . . . . . . . . . . . . .divide by 2

7 0
2 years ago
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