3 years ago

Help me help me please I have to finish this by Tommrow

Mathematics

2 answers:

ira [324]3 years ago

5 0

i did this test already trust me

mixer [17]3 years ago

3 0

Answer:

I am not sure check it

but the answer is A

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Jewel is 7 years old and John is 16 years younger than Dave. One year ago, Dvae's age was twice the sum of Jewel's and John's ag

ivanzaharov [21]

Answer:

Jewel is 7 years old

John is 1 year old

Dave is 17 years old

Step-by-step explanation:

From the question we are told that:

Jewel age is $J=7 years$

John age $J'=(D-16)years$

Dave's age a Year ago

$D-1=2(J-1+J'-1)$

So that Dave.s age this Year could be

$D=2((J-1)+(J'-1))+1$

Simplifying Equation for Dave's age we have

$D=2((7)-1+(D-16)-1)+1$

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Therefore

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$J'=17-16$

$J'=1year old$

John is 1 year old

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