The data set which contains an outlier from the given answer choices is; Choice D; {16, 42, 45, 45, 46, 48}.
<h3>What is an outlier?</h3>
An outlier in a set of data values is a data value which differs significantly from other data points and hence, tends to affect the mean of such set of data values significantly.
On this note, choice D is the set of data values which contains an outlier.
Read more on outliers;
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Convert 3 hours and 30 minutes all into minutes so that would be 210 minutes. You then have 169 miles / 210 minutes. Get the denominator to 1 minutes by dividing by 210 to the top and bottom and you'll get .080476 miles / 1 minute which is the answer.
Answer:
The second time when Luiza reaches a height of 1.2 m = 2 08 s
Step-by-step explanation:
Complete Question
Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.
H(t) = -0.6 cos (2pi/2.5)t + 1.5.
What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.
Solution
Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as
H(t) = -0.6cos(2π/2.5)t + 1.5
What is t when H = 1.2 m
1.2 = -0.6cos(2π/2.5)t + 1.5
0.6cos(2π/2.5)t = 1.2 - 1.5 = -0.3
Cos (2π/2.5)t = (0.3/0.6) = 0.5
Note that in radians,
Cos (π/3) = 0.5
This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,
Cos (5π/3) = 0.5
So,
Cos (2π/2.5)t = Cos (5π/3)
(2π/2.5)t = (5π/3)
(2/2.5) × t = (5/3)
t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.
Hope this Helps!!!
Answer:
An = 5n-18
Step-by-step explanation:
hello :
note : the n th term of an arithmetic sequence is :
An =A1+(n-1)d ....a common difference is : d and A1 the first term
in this exercice : d = 2-(-3)=-3-(-8) =5 A1 = -13
the n th term of an arithmetic sequence is :An =-13+(n-1)(5)
An = 5n -5 -13
An = 5n-18
Answer:
288 in²
Step-by-step explanation:
The formula used to solve this question is :
Lateral Surface Area = s( P1 + P2)
Where s = slant height = 2 inches
P1 and P2 = Perimeter of the bases
Perimeter of base 1 = 4 × length of the end of the small square
4 × 17 inches = 68 inches
Perimeter of base 2 = 4 × length of the end of the large square
4 × 19 inches = 76 inches
Lateral Surface Area = 2 × (68 + 76)
= 2 × 144
= 288 in²