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lara31 [8.8K]
2 years ago
13

Just question eleven .

Mathematics
1 answer:
gregori [183]2 years ago
7 0
I’m pretty sure a is always and b is sometimes.
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|z - 1| = 7z - 13 solve this equation and check for extraneous solutions
Tema [17]

|z - 1|  = 7z - 13
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z - 1 = 7z - 13
and in that case:
- 1 + 13 = 7z - z
12 = 6z
z = 12 \div 6 = 2
or:
z - 1 =  - 7z + 13
and in that case
z + 7z = 13 + 1
8z = 14
z = 14 \times 8 = 1.75
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Which region represents the solution to the given system of inequalities?
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Answer: The intersection region shown in the graph attached is the solution of the system of inequalities.

Step-by-step explanation:

The equation of the line in Slope-Intercept form is:

y=mx+b

Where "m" is the slope and "b" is the y-intercept.

 Given the following system of inequalities:

\left \{ {{x+3y\leq-3 } \atop {x\geq3 }} \right.

We need to graph the lines.

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x+3y=-3

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Since the symbol is \leq, the line must be solid.

The other line is:

x=3

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Since the symbol is \geq, the line must be solid.

We need to substitute a point that is not on the line, into each inequalities. Let's choose the point (0,0).

Then:

0+3(0)\leq-3\\\\0\leq-3

This is false, therefore, we must shade the half that does not contain this point.

0\geq 3

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The intersection region of the solutions (Observe the graph attached) of the given inequalities is the solution of the system of inequalities.

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