Answer:
The resultant velocity of the airplane is 213.41 m/s.
Step-by-step explanation:
Given that,
Velocity of an airplane in east direction, 
Velocity of wind from the north, 
Let east lies in the direction of the positive x-axis and north in the direction of the positive y-axis.
We need to find the resultant velocity of the airplane. Let v is the resultant velocity. It can be calculated as :
v = 213.41 m/s
So, the resultant velocity of the airplane is 213.41 m/s. Hence, this is the required solution.
A ) h = -16 t² + 135 t + 76
Let : h = 0
0 = - 16 t² + 135 t + 76
B ) t 1/2 = (-b+/- √ ( b² - 4 ac ) / ( 2 a )
t 1/2 = (-135 - √(18,225 + 4,864))/ (-32) = ( - 135 - 151.95) / (- 32)=
= (-286.95) / (- 32) = 9.967 ≈ 9.0 s ( other solution is negative )
Answer:
2) 0 = -16 t² + 135 t + 76; 9 s
4.65 would be you decimal if thats what your asking
Answer:
hbw ygav
Step-by-step explanation:
4/3 is your answer because if you simplify 8/6 by dividing both the numerator and the denominator by 2, you will get 4/3.
Also, if you want a mixed number, it is 1 1/3.
Hope this helps!
