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shepuryov [24]
2 years ago
14

{ (1, 1) , (19, 88) , (-3, -5) , (1/2 , -3) , (100, 101) , (200, 9) , (0, -33) }

Mathematics
1 answer:
yuradex [85]2 years ago
4 0

Answer:

i try my best to find the answer and then i will tell just give me some time

Step-by-step explanation:

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Marilyn Manson anybody else a fan ?​
soldi70 [24.7K]

Answer:

wait who is that again?

Step-by-step explanation:

6 0
3 years ago
An unprepared student makes random guesses for the ten​ true-false questions on a quiz. Find the probability that there is at le
hoa [83]

Answer:

0.999

Step-by-step explanation:

At least 1 correct means, 1 correct, 2 correct, 3 correct ... until 10 correct. That would be a long process to calculate.

<em>Instead we use the complement rule to calculate.</em>

<em>P(x\geq1)=1-P(x</em>

<em />

<em>So we need to find P(x<1). So this is getting 0 answers correct, or 10 incorrect.</em>

<em />

In true false question, probablity of correct is 1/2 and incorrect is 1/2, hence,

Probability of 10 incorrect is (1/2)^10

Thus,

P(x\geq1)=1-(\frac{1}{2})^{10}=0.999

So the answer is 0.999 (rounded to nearest thousandth)

3 0
3 years ago
Asymptotes of x=3 and y=-2
dimaraw [331]

Answer:

Both of these values don't have asymptotes.

7 0
3 years ago
Read 2 more answers
If 3a-2b= 8 and a+3b=7 what is the value of 4a+b?
Fittoniya [83]
Step 1: Find the value of one variable in terms of the other.

a+3b=7\\a=7-3b

Step 2: Substitute the value you just found for this variable in the other equation.

3a-2b=8\\3(7-3b)-2b=8\\21-9b-2b=8\\21-11b=8\\21=8+11b\\13=11b\\\frac{13}{11}=b\\ b=1\frac{2}{11}

Step 3: Use your new value for the second variable to find the first.

a+3b=7\\a+3(1\frac{2}{11})=7\\a+3\frac{6}{11}=7\\\\a=3\frac{5}{11}

Now that we know the values for a and b we can find the value of 4a+b.

4a+b\\4(3\frac{5}{11})+1\frac{2}{11}\\12+\frac{20}{11}+1\frac{2}{11}\\\\12+1\frac{9}{11}+1\frac{2}{11}\\\\\boxed{15}
6 0
3 years ago
The joint probability mass function of XX and YY is given by p(1,1)=0p(2,1)=0.1p(3,1)=0.05p(1,2)=0.05p(2,2)=0.3p(3,2)=0.1p(1,3)=
inessss [21]

Answer:

P(Y=1|X=3)=0.125

Step-by-step explanation:

Given :

p(1,1)=0  

p(2,1)=0.1

p(3,1)=0.05

p(1,2)=0.05

p(2,2)=0.3

p(3,2)=0.1

p(1,3)=0.05

p(2,3)=0.1

p(3,3)=0.25

Now we are supposed to find the conditional mass function of Y given X=3 :  P(Y=1|X=3)

P(X=3) = P(X=3,Y=1)+P(X=3,Y=2) +P(X=3,Y=3)

P(X=3)=p(3,1) +p(3,2) +p(3,3)

P(X=3)=0.05+0.1+0.25=0.4

P(Y=1|X=3)=\frac{P(X=3,Y=1)}{P(X=3)} =\frac{p(3,1)}{P(X=3)}=\frac{0.05}{0.4}= 0.125

Hence P(Y=1|X=3)=0.125

8 0
3 years ago
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