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devlian [24]
3 years ago
8

Tell which equation you would choose to solve for one of the variables. Explain.

Mathematics
1 answer:
lapo4ka [179]3 years ago
5 0

Answer:

i would choose to solve x+2y=0 because it is simple and ez

Step-by-step explanation:

i took test and got 100 % brainliest plz

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If a 1 could 1 could a 1 sit on a 2 when a 2 eats a 3 after the 3 sits on 1?
jok3333 [9.3K]

Answer:

no, 2 would be sitting on 1

Step-by-step explanation:

Download docx
7 0
4 years ago
Which is greater 0.205 or 205/1000
Burka [1]
Neither... 

205/1000 equals .205

So they are both the same.

Hope this helps -J
8 0
3 years ago
How many units<br> above the x-axis<br> is the point<br> located at (9, 6)?<br> pls help
svetlana [45]

Answer:

6 units above the x-axis

Step-by-step explanation:

The pair (9,6) are a set of coordinates that indicate how far away from the origin (0,0) the point is.

The coordinates are written (x,y) where 'x' is how far to the left or right of the y-axis (vertical) the point is. The 'y' is how far above or below the x-axis (horizontal) the point is.

So in this case, the set of (9,6) means that the point is located at 9 units to the right of the origin and the y-axis and 6 units above the x-axis

4 0
3 years ago
Read 2 more answers
Solve this -7 3/5 + (-3 2/3)<br> A-10 1/2<br> B-11 4/15<br><br> C- 4 1/2<br> D-10 9/15
otez555 [7]

9514 1404 393

Answer:

  B  -11 4/15

Step-by-step explanation:

  -7 3/5 -3 2/3 = -(7 3/5 +3 2/3)

  = -((7 +3) +(3/5 +2/3)) = -(10 +9/15 +10/15)*

  = -(10 +19/15) = -(10 +1 4/15)

  = -11 4/15

___

* you know at this point that the correct answer is B. The integer part cannot be 10, but must be 11.

8 0
3 years ago
Find the 10th term of the geometric sequence 1, 3, 9, ...
ladessa [460]

Answer:

a(10) = 3^9 = 19683

Step-by-step explanation:

In this sequence each new term is equal to 3 times the previous term.  Thus, 3 is the common ratio.  The first term is 1.

The general formula for the nth term of a geometric sequence i

a(n) = a(1)*r^(n -1), where r is the common ratio.

Here, a(n) = 1*3^(n - 1), and so

the 10th term is

           a(10) = 1*3^(10 - 1), or

            a(10) = 3^9 = 19683

3 0
3 years ago
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