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Gala2k [10]
3 years ago
6

What must be the value of x so that lines a and b are parallel lines cut by transversal f?

Mathematics
1 answer:
34kurt3 years ago
5 0
Ah nice jajxbwkskxne
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What is equivalent to 11 - ( - 3 5/8)?
fredd [130]

Step-by-step explanation:

11 - ( - 3 5/8) will equivalent to

11 + 3⅝ = 14⅝

4 0
2 years ago
Which logarithmic equation is equivalent to the exponential equation below? E^a=28.37
Alex_Xolod [135]
1. To solve this problem, it is important to know that<span> the logarithmic functions  and the exponential functions are inverse. Then, you have:
</span><span> 
 e^a=28.37
</span><span> a=ln(28.37)
</span><span> 
 2. Therefore: </span><span>Which logarithmic equation is equivalent to the exponential equation e^a=28.37? A</span><span>s you can see, the answer for this question is:
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 a=ln(28.37)</span>
7 0
3 years ago
Read 2 more answers
Using the ratio of perfect squares method, what is square root of 22 rounded to the nearest hundredth?
Alja [10]
4+ \frac{22-16}{25-16} = \\\\ 4 + \frac{6}{9} =\\\\4 + \frac{2}{3} &#10;=\\\\ \boxed{\bf{4.67}}
 Using the ratio of perfect squares method, the square root of 22 rounded to the nearest hundredth is 4.67

Hope this helps!! If you have any other questions or would like further explanation just let me know!! :)
5 0
3 years ago
Consider a nuclear power plant that produces 1200 MW of power and has a conversion efficiency of 34 percent (that is, for each u
cestrela7 [59]

Answer:

The amount of nuclear fuel required is 1.24 kg.

Step-by-step explanation:

From the principle of mass energy equivalence we know that energy generated by mass 'm' in an nuclear plant is

E=m\cdot c^2

where

'c' is the speed of light in free space

Since the power plant operates at 1200 MW thus the total energy produced in 1 year equals

E=1200\times 10^6\times 3600\times 24\times 365=3.8\times 10^{16}Joules

Thus using the energy produced in the energy equivalence we get

3.8\times 10^{16}=mass\times (3\times 10^{8})^2\\\\\therefore mass=\frac{3.8\times 10^{16}}{9\times 10^{16}}=0.422kg

Now since the efficiency of conversion is 34% thus the fuel required equals

mass_{required}=\frac{0.422}{0.34}=1.24kg

8 0
3 years ago
Please help me with this problem .
almond37 [142]
Hope you get the answer
4 0
3 years ago
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