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MA_775_DIABLO [31]
3 years ago
5

For each set of three lengths determine if they can be the side lengths of a triangle

Mathematics
1 answer:
Luden [163]3 years ago
5 0

Answer:

1) Yes

2) No

3) Yes

4) Yes

Step-by-step explanation:

Remember the rule: the sum of the two shortest sides must be bigger than the longest side. From there, the answers should be obvious. Just add up the smallest sides for each triplet of lengths and see if that is bigger than the largest side.

7 + 14 > 18, therefore this can be a triangle

3 + 8 < 17, therefore this can't be a triangle

3.2 + 9.0 > 11.5, therefore this can be a triangle

6 + 7 > 8, therefore this can be a triangle

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ivolga24 [154]

Answer:

a. False b. True c. True d. False e. False

Step-by-step explanation:

8 0
3 years ago
The square shown has sides of length 7z^5 decimeters. Find its area
VikaD [51]

For this case we have that by definition, the area of a square is given by:

A = l ^ 2

Where:

l: It's the side of the square

We have, according to the statement data, that:

l = 7z ^ 5 \ dm

Then, the area is given by:

A = (7z ^ 5 \ dm) ^ 2

By definition of power properties we have to:

(a ^ n) ^ m = a ^ {n * m}

So:

A = (7z ^ 5 \ dm) ^ 2 = 49z^{5 * 2} \ dm ^ 2 = 49z^{10} \ dm ^ 2

Answer:

The area of the square is: 49z^{10} \ dm ^ 2

6 0
4 years ago
Need help asap!!!!!!!!!!
yawa3891 [41]

Answer:

x=4

Step-by-step explanation:

The axis of symmetry is always x= the x-coordinate of the vertex

EX:

Vertex: (9,8)

Axis of Symmetry: x=9

4 0
2 years ago
1- find the first term= ?, 90, 540, 3240
Luda [366]

Answer:

1. 15

2. 8

Step-by-step explanation:

The two sequence are geometric progression GP, because they follow a constant multiple (common ratio)

The nth term of a GP is;

Tn = ar^(n-1)

Where;

a = first term

r = common ratio

For the first sequence;

The common ratio r is

r = T3/T2 = 540/90 = 6

r = 6

T2 = ar^(2-1) = ar

T2 = 90 = ar

Substituting the values of r;

90 = a × 6

a = 90/6

a = 15

First term = 15

2. The sam method applies here.

Common ratio r = T3/T2 = 128/32 = 4

r = 4

T2 = ar^(2-1) = ar

T2 = 32 = ar

Substituting the values of r;

32 = a × 4

a = 32/4

a = 8

First term = 8

4 0
3 years ago
One kilogram is approximately equal to 2.21 pounds. Find the number of pounds in 28 kilograms. Round to the nearest tenth of a p
Lunna [17]

Answer:I got 61.88

Step-by-step explanation:

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3 years ago
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