Answer:
(14,-1)
Step-by-step explanation:
okay so first you need to use the "x=4y+10" in the first equation.
Rewrite as
3(4y+10) +11y=7
Distribute the 3(4y+10)
Rewrite as
12y+30
You'll have the equation
12y +30 +11y= 7
Subtract the 7 from both sides
12y+30+11y-7= 0
Combine like terms
23y+23=0
the best thing to do here is divide the equation by 23.
23/23 = 1
you'll have
y + 1 = 0
this simplifies to
y= -1
use this y value to solve for x
the easiest way to do this is start with the equation
x = 4y +10
Substitute the y for -1
x = -4(-1) +10
x = 4 +10
x = 14
the solution point is
(14,-1)
Answer:
56 cm^2
Step-by-step explanation:
Surface area is just finding the areas of each face in a figure. As we are given a net of a figure, it is much easier for us to calculate it.
Area of square base (side^2)
4^2 = 16 cm^2
Area of ONE triangular face (1/2 x b x h):
1/2 x 4 x 5 = 10 cm^2
Multiply that by 4 because we have 4 triangular faces: 10 cm^2 x 4 = 40 cm^2
ADD all the areas of triangles and square:
16 cm^2 + 40 cm^2 = 56 cm^2
HOPE THIS HELPS
Have a nice day!
Step-by-step explanation:
Decimals are great for when you are dealing with money and want to round up, and fractions are used when baking (such as need 1/4 or a half cup of something)
Answer:
22% = 0.22
Step-by-step explanation:
Lat'e express all the given numbers in decimal form so we understand how they are located on the number line.
We start with 2/11 , since the number we are looking for has to be larger than this \, and smaller than 1.42:
So we understand that we are looking for a number that can be placed between the lower boundary (0.181818...) and the upper boundary (1.42) on the number line. That is: we are looking for a number greater than 0.18181818... and less than 1.42.
Now let's look at each of the given options (also writing them in decimal form to facilitate the comparison with the lower and upper boundaries we just found):
This number is grater than the upper boundary given to us (1.42), it would be placed to the right of 1.42 on the number line. Therefore we discard it for not being in the requested interval (section) of the number line.
0.153 is already in decimal form, and clearly less than (thus to be placed on the left of) the lower boundary (0.181818...) of the requested interval. Therefore we discard it for not being in the requested interval (section) of the number line.
22% in decimal form is written as: 
. This number is greater than the lower boundary (0.181818...) and also less than the upper boundary (1.42). Therefore it is a choice that would make the sentence true.
which is clearly greater than the upper boundary of the interval, so we discard it.
