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natali 33 [55]
2 years ago
10

We can buy 32 ounces of lemonade for $6.08 How much does it cost per ounce.

Mathematics
1 answer:
cricket20 [7]2 years ago
6 0

Answer: $0.19

Step-by-step explanation: divide 32 by $6.08

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HELP PLEASE!
amid [387]
D. 60

when subtracting a negative from a positive use KCC 
K eep
C hange
C hange

you keep the first number change the subtraction to a addition and make the negative a positive

35-(-25)
=======
35+(-25)
=======
35+25
=======
60
7 0
3 years ago
The range of the function f(k) = k2 + 2k + 1 is {25, 64}. What is the function’s domain?
s344n2d4d5 [400]
{k^2 + 2k + 1 = 25, k^2 + 2k + 1 = 64}
{k^2 + 2k - 24 = 0, k^2 + 2k - 63 = 0}
{(k - 4)(k + 6) = 0, (k - 7)(k + 9) = 0}
{k = -6, 4, -9, 7)
Therefore, range = {-9, -6, 4, 7)
3 0
3 years ago
Alguien me podría ayudar a resolver esto? Es urgente.
choli [55]

Answer:

2x+y-3=0

Step-by-step explanation:

4x+2y-6=0

2x+y-3=0

4 0
3 years ago
What is a reasonable estimate for the solution? O (1,-3/4) O (-3/4,1) O (-1,3/4) O (3/4,-1)​
Zina [86]

Answer:

See Explanation

Step-by-step explanation:

Your question is incomplete, as the equations or graph or table(s) were not given.

However, I'll give a general way of solving this.

Take for instance, the equations are:

y = \frac{4}{3}x - 1

y = \frac{2}{3}x - \frac{1}{2}

To do this, we start by equating both equations.

y = y

i.e.

\frac{4}{3}x - 1= \frac{2}{3}x - \frac{1}{2}

Collect Like Terms

\frac{4}{3}x - \frac{2}{3}x= 1 - \frac{1}{2}

Take LCM

\frac{4x- 2x}{3}= \frac{2 - 1}{2}

\frac{2x}{3}= \frac{1}{2}

Cross Multiply

2x * 2 = 3 * 1

4x = 3

Make x the subject

x = \frac{3}{4}

Substitute 3/4 for x in y = \frac{4}{3}x - 1

y = \frac{4}{3} * \frac{3}{4} - 1

y = 1 - 1

y = 0

Hence:

(x,y) = (\frac{3}{4},0)

6 0
2 years ago
Which series of transformations will not map figure H onto itself?
chubhunter [2.5K]

Answer:

(x + 0, y − 2), reflection over y = 1

Step-by-step explanation:

H will be shifted down 2 units and then reflected over y = 1, which maps H into itself

3 0
3 years ago
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