ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions
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1 answer:
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Answer:
the lower right matrix is the third correct choice
Step-by-step explanation:
Your problem statement shows that you have correctly selected the matrices representing the initial problem setup (middle left) and the problem solution (middle right).
Of the remaining matrices, the upper left is an incorrect setup, and the lower left is an incorrect solution matrix.
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We notice that in the remaining matrices on the right that the (2,3) term is 0, and the (3,2) and (3,3) terms are both 1.
The easiest way to get a 0 in the 3rd column of row 2 is to add the first row to the second. When you do that, you get ...
Already, we see that the second row matches that in the lower right matrix.
The easiest way to get 1's in the last row is to divide that row by 0.15. When we do that, the (3,4) entry becomes 2100/0.15 = 14000, matching exactly the lower right matrix.
The correct choices here are the two you have selected, and <em>the lower right matrix</em>.
A standard deck of cards has 52 cards. Half of the deck has red cards and half has black cards. So the first probability would be 26/52, or 1/2 (simplified, it's half the deck).
Then you put the card back and choose a 3. There are 4 cards with the number 3 in the deck. So it's 4/52.
Then you multiply both the probabilities
26/52 x 4/52 =
= 1/26
Then you put the card back and choose a 3. There are 4 cards with the number 3 in the deck. So it's 4/52.
Then you multiply both the probabilities
26/52 x 4/52 =