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STatiana [176]
2 years ago
14

What is 1 and 3/4 x 1 and 1/3

Mathematics
1 answer:
mart [117]2 years ago
7 0

Answer:

7/3 or 2 1/3

Step-by-step explanation:

change 1 3/4 to an improper fraction → 7/4

change 1 1/3 to an improper fraction → 4/3

multiply: \frac{(7x4)}{(4x3)} = 28/12 or 7/3 which is 2 1/3

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Which equation represents a line perpendicular to the line shown on the graph?
Vadim26 [7]

Answer:

See description below.

Step-by-step explanation:

To choose the correct equation, find the slope of the line on the graph. Identify two points on the line. Then subtract to find their rate of change using the slope formula.

m=\frac{y_2-y_1}{x_2-x_1}

When you know the slope, find the negative reciprocal. For example, if the slope is 2/1 then the negative reciprocal is -1/2. This is the slope of a perpendicular line to a line with slope 2. Choose the equation which has this same slope.

Example:

y = 2x -1

y= -1/2 +5

4 0
3 years ago
. If mZJ= (7x + 13)", mZK = (83 - 2x), and
OLga [1]

Answer:

  • m∠J = 76°
  • m∠K = 65°

Step-by-step explanation:

The sum of angle measures is ...

  (7x +13)° +(83 -2x)° = 141°

  5x +96 = 141 . . . . . collect terms, divide by °

  5x = 45 . . . . . . . . . subtract 96

  x = 9 . . . . . . . . . . . divide by 5

  7x +13 = 7·9 +13 = 76 . . . . . find m∠J

  m∠J = 76°

  m∠K = 141° -76°

  m∠K = 65°

8 0
3 years ago
What is the simplified form of left parenthesis 27 x to the power of negative six end power y to the power of 12 end power right
Tanzania [10]
Hello,
Please, see the attached file,
Thanks.

5 0
3 years ago
Question
maria [59]

Answer:

y = m x + b equation of a straight line

m m' = -1    condition for perpendicular lines

If y = 4 x - 7     then m = 4 so m' = -.25

Y = -.25 X + A      we need to find A

A = Y + .25 * 8 = 2 + 2 = 4

Y = -.25 X + 4

Check:

2 = -.25 * 8 + 4 = -2 + 4 = 2

3 0
3 years ago
Round 43.628 to the thousands place. A. 40.000 O O B. 43.000 O O C. 43.600 D. 44.000
VARVARA [1.3K]

Answer:

A) 40000

Step-by-step explanation:

this is the answer to your question

6 0
2 years ago
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