Which number has a 4 that is one tenth the value of the 4 in 438?
1 answer:
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Answer:
y = (x -2)^2 +4
Step-by-step explanation:
The vertex form of the equation of a parabola is ...
y = a(x -h)^2 +k
for vertex (h, k) and vertical scale factor "a". When a > 0, the parabola opens upward.
One equation for your parabola could be ...
y = (x -2)^2 +4
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In standard form this one is ...
y = x^2 -4x +8
