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Naily [24]
2 years ago
6

Work out the value of x- pls I will give Brainliest!!!

Mathematics
1 answer:
lara31 [8.8K]2 years ago
7 0

3x = 2x ( alternate exterior angel)

3x - 2x = 0

x = 0

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53x52 step by step plzzz
Zigmanuir [339]

Answer: here you go i tried my best

Step-by-step explanation:

3 0
2 years ago
Find each measurement indicated. Round your answers to the nearest tenth.
Crazy boy [7]

Answer:

A

Step-by-step explanation:

Find AB using the Law of Sine:

\frac{AB}{sin(C)} = \frac{AC}{sin(B)}

Thus:

\frac{AB}{sin(40)} = \frac{47}{sin(103)}

Multiply both sides by sin(40)

\frac{AB}{sin(40)}*sin(40) = \frac{47}{sin(103)}*sin(40)

AB = \frac{47*Sin(40)}{sin(103)}

AB = 31.0056916 ≈ 31.0 cm (nearest tenth)

6 0
3 years ago
What is the equation of the line that passes through the point (-4,-2) and has a<br> slope of -1/2?
Soloha48 [4]

Answer:

y =  -  \frac{1}{2} x

8 0
3 years ago
What is the height of a projectile in 4 seconds if its initial height is 125 ft and it has a velocity of 300 ft per second? 972
andre [41]

Answer:

B. 1069 feet

Step-by-step explanation:

d=v_ot+\dfrac{1}{2}at^2 \\\\d=(300)(4)+\dfrac{1}{2}(-32)(4)^2 \\\\d=1200-256=944

Adding the initial 125 feet to this, you get a total height of 1069 feet. Hope this helps!

4 0
3 years ago
The diagonals of a rhombus measures 6cm and 8cm, what is the perimeter of this rhombus?
Kamila [148]
<h2><u>Diagram</u><u>:</u><u>-</u></h2>

\setlength{\unitlength}{1 cm}\begin{picture}(20,15)\thicklines\qbezier(1,1)(1,1)(6,1)\qbezier(1,1)(1,1)(1.6,4)\qbezier(1.6,4)(1.6,4)(6.6,4)\qbezier(6,1)(6,1)(6.6,4)\qbezier(6.6,4)(6.6,4)(1,1)\qbezier(1.6,4)(1.6,4)(6,1)\put(0.7,0.5){\sf A}\put(6,0.5){\sf B}\put(1.4,4.3){\sf D}\put(6.6,4.3){\sf C}\end{picture}

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

The diagonals of the Rhombus= d1 & d2=6cm and 8cm

Let the Side=a

As we know that in a Rhombus

{\boxed{\sf side=\sqrt {\left ({\dfrac{d1}{2}}\right)^2+\left ({\dfrac {d2}{2}}\right)^2}}}

  • Substitute the values

{:}\longmapsto\sf a=\sqrt {\left ({\dfrac {6}{2}}\right)^2+\left ({\dfrac {8}{2}}\right)^2 }

{:}\longmapsto\sf a=\sqrt {(3)^2+(4)^2}

{:}\longmapsto\sf a=\sqrt {9+16}

{:}\longmapsto\sf a=\sqrt{25}

{:}\longmapsto\sf a=5cm

<h2>_____________</h2><h3>Again </h3>

we know that in a Rhombus

\boxed{\sf Perimeter=4a}

  • Substitute the values

{:}\longmapsto\sf Perimeter=4×5

{:}\longmapsto\sf Perimeter=20cm

\thereforePerimeter of the rectangle is 20cm.

5 0
2 years ago
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