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2 years ago

6

Work out the value of x- pls I will give Brainliest!!!

1 answer:

lara31 [8.8K]2 years ago

7 0

3x = 2x ( alternate exterior angel)

3x - 2x = 0

x = 0

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53x52 step by step plzzz

Zigmanuir [339]

Answer: here you go i tried my best

Step-by-step explanation:

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2 years ago

Find each measurement indicated. Round your answers to the nearest tenth.

Crazy boy [7]

Answer:

A

Step-by-step explanation:

Find AB using the Law of Sine:

$\frac{AB}{sin(C)} = \frac{AC}{sin(B)}$

Thus:

$\frac{AB}{sin(40)} = \frac{47}{sin(103)}$

Multiply both sides by sin(40)

$\frac{AB}{sin(40)}*sin(40) = \frac{47}{sin(103)}*sin(40)$

$AB = \frac{47*Sin(40)}{sin(103)}$

AB = 31.0056916 ≈ 31.0 cm (nearest tenth)

6 0

3 years ago

What is the equation of the line that passes through the point (-4,-2) and has a<br> slope of -1/2?

Soloha48 [4]

Answer:

$y = - \frac{1}{2} x$

8 0

3 years ago

What is the height of a projectile in 4 seconds if its initial height is 125 ft and it has a velocity of 300 ft per second? 972

andre [41]

Answer:

B. 1069 feet

Step-by-step explanation:

$d=v_ot+\dfrac{1}{2}at^2 \\\\d=(300)(4)+\dfrac{1}{2}(-32)(4)^2 \\\\d=1200-256=944$

Adding the initial 125 feet to this, you get a total height of 1069 feet. Hope this helps!

4 0

3 years ago

The diagonals of a rhombus measures 6cm and 8cm, what is the perimeter of this rhombus?

Kamila [148]

<h2><u>Diagram</u><u>:</u><u>-</u></h2>

$\setlength{\unitlength}{1 cm}\begin{picture}(20,15)\thicklines\qbezier(1,1)(1,1)(6,1)\qbezier(1,1)(1,1)(1.6,4)\qbezier(1.6,4)(1.6,4)(6.6,4)\qbezier(6,1)(6,1)(6.6,4)\qbezier(6.6,4)(6.6,4)(1,1)\qbezier(1.6,4)(1.6,4)(6,1)\put(0.7,0.5){\sf A}\put(6,0.5){\sf B}\put(1.4,4.3){\sf D}\put(6.6,4.3){\sf C}\end{picture}$

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

The diagonals of the Rhombus= d1 & d2=6cm and 8cm

Let the Side=a

As we know that in a Rhombus

${\boxed{\sf side=\sqrt {\left ({\dfrac{d1}{2}}\right)^2+\left ({\dfrac {d2}{2}}\right)^2}}}$

Substitute the values

${:}\longmapsto$ $\sf a=\sqrt {\left ({\dfrac {6}{2}}\right)^2+\left ({\dfrac {8}{2}}\right)^2 }$

${:}\longmapsto$ $\sf a=\sqrt {(3)^2+(4)^2}$

${:}\longmapsto$ $\sf a=\sqrt {9+16}$

${:}\longmapsto$ $\sf a=\sqrt{25}$

${:}\longmapsto$ $\sf a=5cm$

<h2>_____________</h2><h3>Again </h3>

we know that in a Rhombus

$\boxed{\sf Perimeter=4a}$

Substitute the values

${:}\longmapsto$ $\sf Perimeter=4×5$

${:}\longmapsto$ $\sf Perimeter=20cm$

$\therefore$ Perimeter of the rectangle is 20cm.

5 0

2 years ago