All categories

2 years ago

Divide 70 in ratio of 3:5:6

Mathematics

1 answer:

lora16 [44]2 years ago

5 0

Answer:

Part 1 = 15

Part 2 = 25

Part 3 = 30

Step-by-step explanation:

Ratio = 3 : 5 : 6

Sum of the ratio terms = 3 + 5 + 6 = 14

Then,

$\cdot \:\: \frac{3 * 70}{14} =15\\ \\\cdot \:\: \frac{5 * 70}{14} =25\\ \\\cdot \:\: \frac{6 * 70}{14} =30$

You might be interested in

What is the maximum value of P = 24x + 30y, given the constraints on x and y listed below? x+y (less than or equal to) 5 x-y (gr

valentina_108 [34]

Answer:

Step-by-step explanation:

We have to first find the vertices of the feasible region before we can determine the max value of P(x, y). We will graph all 4 of those inequalities in a coordinate plane and when we do that we find that the region of feasibility is bordered by the vertices (0, 0), (0, 1), (2, 3), and (5, 0). Filling each x and y value into our function will give us the max value of that function.

Obviously, when we sub in (0, 0). we get that P(x, y) = 0.

When we sub in (0, 1) we get 24(0) + 30(1) = 30.

When we sub in (2, 3) we get 24(2) + 30(3) = 138.

When we sub in (5, 0) we get 24(5) + 30(0) = 120.

Obviously, the vertex of (2, 3) maximized our function for a value of 138.

6 0

3 years ago

Given that 1 x2 dx 0 = 1 3 , use this fact and the properties of integrals to evaluate 1 (4 − 6x2) dx. 0

Debora [2.8K]

So, the definite integral $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Given that

$\int\limits^1_0 {x^{2} } \, dx = 13$

We find

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx$

<h3>Definite integrals </h3>

Definite integrals are integral values that are obtained by integrating a function between two values.

So, $Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6\int\limits^1_0 {x^{2} } \, dx$

Since

$\int\limits^1_0 {x^{2} } \, dx = 13$ ,

Substituting this into the equation the equation, we have

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx = 4 - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6 X 13 \\= 4 - 78\\= -74$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Learn more about definite integrals here:

brainly.com/question/17074932

4 0

2 years ago

What is 4 minus 1 5/12

klasskru [66]

Answer: 2 and 7/12

Step-by-step explanation: To subtract 4 - 1 and 5/12, first subtract the fractions. Since 4 has no fraction, imagine the fraction 0/12.

Notice however that we can't subtract 0/12 - 5/12.

So, let's rewrite 4 and 0/12 as 3 + 1 and 0/12 or 3 + 12/12 by changing 1 and 0/12 into an improper fraction.

Now we have 3 and 12/12 - 1 and 5/12.

Now we can subtract our fractions 12/12 - 5/12 and we get 7/12. Next we subtract our whole numbers 4 - 1 to get 3.

So 5 - 1 and 5/12 is 2 and 7/12.

4 0

3 years ago

Read 2 more answers

Need help :))))))))

tatiyna

easy

No need to explain

6 0

2 years ago

Given that

VLD [36.1K]

-17/2

Step-by-step explanation:

30-8(8)+4y

30=64+4y

30-64=4y

-34=4y

y= -34/4

y= -17/2

hope it helps!

6 0

3 years ago