Answer:
No of white balls = 5
Step-by-step explanation:
Given that,
Total no of red balls = 4
Total no of green balls = 6
The probability of not drawing a white ball in one draw be, 
We need to find the number of white balls. Let there are x balls.
The probability of drawing a white ball = 1 - the probability of not drawing a white ball
= 1 -2/3
= 1/3
Using the formula for solving probability of having a white ball.

Hence, there are 5 white balls.
Answer:
C
Step-by-step explanation:
Since GJ bisects ∠ FGH , then ∠ FGJ = ∠ JGH = x + 14
∠ FGH = ∠ FGJ + ∠ JGH , substitute values
4x + 16 = x + 14 + x + 14 = 2x + 28 ( subtract 2x from both sides )
2x + 16 = 28 ( subtract 16 from both sides )
2x = 12 ( divide both sides by 2 )
x = 6
Thus
∠ FGJ = x + 14 = 6 + 14 = 20° → C
Answer:
0.1507 or 15.07%.
Step-by-step explanation:
We have been given that the manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .016 millimeters. To be acceptable the diameter needs to be between 21.97 and 22.03 millimeters.
First of all, we will find z-scores for data points using z-score formula.
, where,
z = z-score,
x = Sample score,
= Mean,
= Standard deviation.



Let us find z-score of data point 22.03.



Using probability formula
, we will get:

Therefore, the probability that a randomly selected ball bearing will be acceptable is 0.1507 or 15.07%.
Answer:
D. The last 26/8, 3-32, -Pi, -4 2/3
Step-by-step explanation:
26/8= 3.25
3-32=3.17
-Pi= -3.14
-4 2/3= -4.67