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lions [1.4K]
2 years ago
7

Helpppp me plssssssssssssssssssssssssss

Mathematics
1 answer:
Thepotemich [5.8K]2 years ago
3 0

Answer: The down payment is 50% of the purchase price

Step-by-step explanation: Sure hope this helps you. And mark me as briniest

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A car dealer just took delivery on forty new cars. He plans to put four of these cars on display at the front of the lot. In how
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Factor 5x2 + 10x + 2x + 4
Genrish500 [490]

Answer:

(5 x + 2) (x + 2)

Step-by-step explanation:

Factor the following:

5 x^2 + 10 x + 2 x + 4

10 x + 2 x = 12 x:

5 x^2 + 12 x + 4

Factor the quadratic 5 x^2 + 12 x + 4. The coefficient of x^2 is 5 and the constant term is 4. The product of 5 and 4 is 20. The factors of 20 which sum to 12 are 2 and 10. So 5 x^2 + 12 x + 4 = 5 x^2 + 10 x + 2 x + 4 = 2 (5 x + 2) + x (5 x + 2):

2 (5 x + 2) + x (5 x + 2)

Factor 5 x + 2 from 2 (5 x + 2) + x (5 x + 2):

Answer: (5 x + 2) (x + 2)

5 0
3 years ago
Name a point that is 20 units away from (5,-2)​
Fudgin [204]

Answer:

Distance between both points is 20units.

Applying the Distance between Points Formula

d= √(y₂-y₁)²+(x₂-x₁)²

x₁= 5 y₁=–2

x₂= ? y₂= ?

20 = √ [y -(-2)]² + (x - 5)²

Taking the square of both sides to eliminate the square root on the right.

20² = ( y + 2)² + (x - 5)²

400 = y² + 4y + 4 + x² – 10x + 25.

400 = x² + y² – 10x + 4y + 29.

x² + y² – 10x + 4y = 400 – 29

x² + y² – 10x + 4y = 371--------------eqn 1.

We called that eqn 1 cause we need another equation to solve this.

To solve an Equation with 2 variables... You need 2 equation.

To solve that of 3 variables.... you need 3 equations(Basic Math Rules).

We're dealing with 2 variables in this case(x, y).

Now

We'd need to think in order to create another equation that'll satisfy the distance or point.

We know that the distance between both Points(known and unknown) is 20.

Half that distance is 10.

The distance of 10 will occur at the center of these 2 points.

So lets apply the formula for Mid point to get the coordinate of the center.

Midpoint

let p be the x position and q be the y position of the midpoint

p = (x₁ + x₂)/2. q = (y₁ + y₂)/2

Starting from the know point (5 , -2)

x₁=5 y₁=–2

p = (5 + x)/2. q = (–2 + y)/2

p = (x + 5)/2 q = (y–2)/2.

This is the coordinate of the Midpoint.

Now We know that the distance between (5, -2) and [(x + 5)/2 , (y–2)/2] is 10(midpoint).

Applying the distance between points again.

d = √(y₂ - y₁)² + (x₂ - x₁)²

x₁= 5 y₁= -2

x₂= (x + 5)/2 y₂= (y–2)/2

10 = √[(y–2)/2 -(-2)]² + [ (x+5)/2 – 5)]²

10 = √[(y–2)/2 + 2]² + [(x+5)/2 – 5)]²

Squaring both sides to remove square root on the right and also Taking the LCM in each bracket

We have

10² = [ (y + 2)/2]² + [ (x–5)/2]²

Distributing the "2" on the denominator to each individual number in the parentheses.

100 = (y/2 + 1)² + (x/2 – 5/2)²

100 = y²/4 + y + 1 + x²/4 –5x/2 + 25/4.

Multiply through by 4 to clear fractions.

400 = y² + 4y + 4 + x² – 10x + 25

Rearranging

x² + y² – 10x + 4y = 371.

Hmm...

Equation 1 and 2 Are the Same.

Something is Wrong!

Pls Recheck the Question

I do believe that One value of the unknown point should be given.

I maybe be wrong somewhere else too.

Pls correct in the comment section if you spot it.

7 0
3 years ago
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