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bearhunter [10]

3 years ago

13

a passenger train leaves a depot 4 h after a freight train leaves the same depot. the passenger train is traveling 32 mph faster

than the freight train. find the rate of each train if the passenger train overtakes the freight train in 4h

1 answer:

VARVARA [1.3K]3 years ago

6 0

Answer:

use this

Step-by-step explanation:

velocity = distance / time…. So distance = velocity x time

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64y-4+2y=-2<br> solve the equation

-Dominant- [34]

Answer:33=y

Step 64u to 2y you get 66y the. -2+4 and you get 2 which is 66y=2. Now divide 66 by two to get 33=y

6 0

4 years ago

Read 2 more answers

7n + 6(n+4) -15 <br><br> how do i solve this with a step by step example

GrogVix [38]

Answer:

13n +9

Step-by-step explanation:

There is nothing to solve. We can simplify the expression by eliminating parentheses and combining like terms.

7n +6(n +4) -15 . . . . . . given

7n +6n +6(4) -15 . . . . use the distributive property

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8 0

2 years ago

The lines graphed below are parallel. The slope of the red line is - What is

PIT_PIT [208]

Answer:

C. -4/3

Step-by-step explanation:

Parallel lines have the same gradient (steepness) and this means that they will never intersect.

Hope this helps!

7 0

3 years ago

A right triangle has one side of length 7 and a hypotenuse of 14. what are its angles? what is the exact length of the third sid

galina1969 [7]

The exact length:12.1

8 0

4 years ago

Suppose an isosceles triangle has two sides of length 42 and 35, and that the angle between these two sides is 120 degree. what

Citrus2011 [14]

Suppose that a=42, b=35, c is unknown, and C = 120°

$c^2 = a^2 + b^2 -2ab(cosC)$

$c^2 = 42^2 + 35^2 -(2*42*35*cos120)

(cos120=-0.5)

c^2 = 1764 + 1225 -(2940*cos120)

c^2 = 2989 -(2940*-0.5)

c^2 = 2989+1470

c^2=4459

c= \sqrt{c^2} 

c=\sqrt{4459}$

3 0

4 years ago