Question

Which expression is equivalent to log Subscript w Baseline StartFraction (x squared minus 6) Superscript 4 Baseline Over RootIndex 3 StartRoot x squared 8 EndRoot EndFraction?.

Answer 1

The logarithmic expression $\rm log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2-8}}$ can be expressed as $\rm 4log_w{(x^2-6)} - {\dfrac{1}{3}}log_w(x^2-8)$.

Given to us

$\rm log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2-8}}$

Which expression is equivalent to $\rm log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2-8}}$ ?

To solve the problem we will use the basic logarithmic properties,

$\rm log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2-8}}$

Using the logarithmic property $\rm log_a\dfrac{x}{y} = log_ax-log_ay$,

$=\rm log_w{(x^2-6)^4} - log_w{\sqrt[3]{x^2-8}}$

Using the exponential property $\sqrt[m]{a^n} = a^{\frac{n}{m}}$,

$=\rm log_w{(x^2-6)^4} - log_w(x^2-8)^{\dfrac{1}{3}}$

Using the logarithmic property $\rm log_aB^x = xlog_aB$,

$=\rm 4log_w{(x^2-6)} - {\dfrac{1}{3}}log_w(x^2-8)$

Hence, the logarithmic expression $\rm log_w\dfrac{(x^2-6)^4}{\sqrt[3]{x^2-8}}$ can be expressed as $\rm 4log_w{(x^2-6)} - {\dfrac{1}{3}}log_w(x^2-8)$.

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