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2 years ago

11

Jordan volunteered for the same amount of time each day for 7 days. If he volunteered for 329 minutes altogether, how many minut

es did he volunteer for each day?

1 answer:

AVprozaik [17]2 years ago

3 0

Answer:

47

Step-by-step explanation:

Just divide 329 by 7

That gives you 47

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(-7)^-1 without an exponent

Verizon [17]

Put the negative exponent as the denominator in a fraction, so you'd get -7/1

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3 years ago

For every 7 glasses wearers in a Classroom,there are about 13 non glasses wearers.If there are 32 students in a entire class how

Alla [95]

Answer:

21 With glasses

Step-by-step explanation:

32/20=1.6

1.6•7=11.2 Without Glasses

1.6•13=20.8 With Glasses

20.8 rounded to nearest whole number=21

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3 years ago

What is the slope of a line that is parallel to the line y=3/4x+2

MariettaO [177]

The slope is m=3/4. Hope this helped you with your work let me know if I got the answer correct.

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3 years ago

Read 2 more answers

A circle with radius of 3cm sits inside a 8 cm x 7cm rectangle what is the area of the shaded region?

Temka [501]

Answer:

You have to say which one is the shaded region the circle or the rectangle

Step-by-step explanation:

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3 years ago

Find a polynomial with integer coefficients that satisfies the given conditions. R has degree 4 and zeros 3 − 3i and 2, with 2 a

dolphi86 [110]

Answer:

The required polynomial is $P(x)=x^4-10x^3+46x^2-96x+72$ .

Step-by-step explanation:

If a polynomial has degree n and $c_1,c_2,...,c_n$ are zeroes of the polynomial, then the polynomial is defined as

$P(x)=a(x-c_1)(x-c_2)...(x-x_n)$

It is given that the polynomial R has degree 4 and zeros 3 − 3i and 2. The multiplicity of zero 2 is 2.

According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.

Since 3-3i is zero, therefore 3+3i is also a zero.

Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is

$R(x)=(x-3+3i)(x-3-3i)(x-2)(x-2)$

$R(x)=((x-3)+3i)((x-3)-3i)(x-2)^2$

$R(x)=(x-3)^2-(3i)^2((x-3)-3i)(x-2)^2$ $[a^2-b^2=(a-b)(a+b)]$

$R(x)=(x^2-6x+9-9(i)^2((x-3)-3i)(x-2)^2$

$R(x)=(x^2-6x+18)(x^2-4x+4)$ $[i^2=-1]$

$R(x)=(x^2-6x+18)(x^2-4x+4)$

$R(x)=x^4-10x^3+46x^2-96x+72$

Therefore the required polynomial is $P(x)=x^4-10x^3+46x^2-96x+72$ .

3 0

3 years ago