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ad-work [718]
2 years ago
6

PLEASE I NEED HELPPP !!!!! please help

Mathematics
2 answers:
weeeeeb [17]2 years ago
7 0
Yeah we have to see it properly to give you the right answer
Strike441 [17]2 years ago
3 0
Can you take a better picture because it’s hard to see where the line marks. or tell me the coordinates.
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The table shows how many males and females attended two different movies. How would you find the joint relative frequency of bei
kirza4 [7]

Answer:

B. Divide 124 by 229.

Step-by-step explanation:

Given the table

\begin{array}{cccc}&\text{Action}&\text{Drama}&\text{Total}\\ \\\text{Male}&105&124&229\\ \\\text{Female}&99&151&250\\ \\\text{Total}&204&275&479\end{array}

The <u>joint relative frequency</u> is the ratio of the frequency in a particular category and the total number of data values.

The total number of males =229

The number of males that like drama =124

So, to find the joint relative frequency of being male and attending a drama movie, you should divide 124 by 229.

8 0
3 years ago
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Additive inverse of 1/3
Xelga [282]

The additive inverse of 1/3 is 3/1.

Hope this helps you!

:)

4 0
3 years ago
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Can anyone tell me who danink 662 is and how do you know him​
neonofarm [45]

Answer:

He is a person with a profile on brainly. And I do believe that I have him as one of my friends*

    *or not :)

Step-by-step explanation:

8 0
3 years ago
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Hi i just need help checking if my answer is correct I have been working on a implicit diffrention problem and I need some help.
SSSSS [86.1K]

Answer:

  \dfrac{dy}{dx}=\dfrac{-4x^3y+2y^3+3x^2y^3}{x^4-6xy^2-3x^3y^2}

Step-by-step explanation:

Normally, when I do this, I differentiate each term first with respect to x then with respect to y. In this solution, I differentiated the entire expression with respect to x, then with respect to y. That makes separating the dx and dy coefficients much easier, so the solution almost falls into your lap.

  -x^4 y + 2 x y^3 + x^3 y^3=0 \qquad\text{given}\\\\(-4x^3y+2y^3+3x^2y^3)dx+(-x^4+6xy^2+3x^3y^2)dy=0\\\\(-4x^3y+2y^3+3x^2y^3)dx=(x^4-6xy^2-3x^3y^2)dy\\\\\boxed{\dfrac{dy}{dx}=\dfrac{-4x^3y+2y^3+3x^2y^3}{x^4-6xy^2-3x^3y^2}}

6 0
2 years ago
ANSWER ASAP GIVING BRAILIEST AND STUFF!
MrRissso [65]
The answer multiplied if it doubled the its times 2 tripled it’s timeS 3 quadruple then times 4
8 0
3 years ago
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