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2 years ago

PLEASE I NEED HELPPP !!!!! please help

Mathematics

2 answers:

weeeeeb [17]2 years ago

7 0

Yeah we have to see it properly to give you the right answer

Strike441 [17]2 years ago

3 0

Can you take a better picture because it’s hard to see where the line marks. or tell me the coordinates.

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22 gallons of gas cost $65.56 what is the unit rate for one gallon of gas

Kitty [74]

Hey there!

If we would want to find out what it would be, we would have to divide it.

Your correct answer would be (2.98)

I did 65.56/22.

Hope this helps you!

7 0

3 years ago

Read 2 more answers

URGENT<br> Which of the following statements is true? Select all that apply.

valina [46]

Answer:

C is true also

Step-by-step explanation:

3 0

3 years ago

Can Somebody Please Help

Free_Kalibri [48]

Answer:

We have to put the data for purchased item in a frequency table.

Step-by-step explanation:

The diagram is attached below.

Firstly we have to see that how many customers fall under range $0 to 5$ .

Then $5 to 10$ .

Then $10 to 15$ .

Finally

$15 to 20$ .

If we go through the items purchased by customers we can see that item ranges from $0 to 5$ have $4$ customers.

Item purchased range from $5 to 10$ have $2$ customers.

Item purchased range from $10 to 15$ have $7$ customers.

Item purchased range from $15 to 20$ have $1$ customers.

Total number of customers = $14$

As we have total $14$ number of customers and they have varied quantity of items purchased.

6 0

3 years ago

I need to solve for 3x+7=-x-1

Andrew [12]

3x+7=-x-1

move -x to the other side

sign changes from -x to +x

3x+x+7=-x+x-1

3x+x+7=-1

4x+7=-1

move 7 to the other side

sign changes from +7 to -7

4x+7-7=-1-7

4x=-8

Divide by 4 for both sides

4x/4=-8/4

Answer: x=-2

3 0

3 years ago

The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as

bija089 [108]

Answer:

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(score of the 36 golfers was between 70 and 71)

$\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}$

$P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%$

$P(70 \leq x \leq 71) = 47.7\%$

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

8 0

3 years ago