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4 years ago

10

Can you guys please help me with number 10 please I beg

2 answers:

Andreas93 [3]4 years ago

7 0

You would need to subtract week ones amount of rainfall from week fours amount of rainfall because it is asking how much more so you would subtract them.

alexdok [17]4 years ago

4 0

Answer:

1.47

The drawing will help

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Find the midpoint of the segment connecting (4,7) to (-2,3).

KonstantinChe [14]

If you put 2 points on a graph paper and connect them, you can find the midpoint pretty easily

8 0

3 years ago

Help with this one!<br><br><br> Show steps if you can pls :)

lianna [129]

Answer:

110%

Step-by-step explanation:

just divide by 2

20/2 = 10

22/2 = 11

so x% of 10 = 11

1.10 just like the last problem

110%

4 0

3 years ago

Simplify the expression

erastova [34]

Answer : A

We need to simplify the given expression

Lets factor numerator first

$2x^2-5x-3$ =(2x+1)(x-3)

$x^2+8x+15$ =(x+5)(x+3)

Now we factor the denominator

$x^2+x-20$ =(x+5)(x-4)

$2x^2+9x+4$ =(2x+1)(x-4)

Now we simplify it

$\frac{(2x+1)(x-3)}{(x+5)(x-4)} * \frac{(x+5)(x+3)}{(2x+1)(x-4)}$

Now cancel out same factors. so we left with

$\frac{(x+3)(x-3)}{(x+4)(x-4)} }$

Now multiply the factors

$\frac{x^2-9}{x^2-16} }$

6 0

3 years ago

1-58. Mr. Wright was making a table to figure out how much it costs to send a certain numt

Drupady [299]

A table of values can be used to represent variables that are directly proportional.

The complete table of proportions is:

$\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]$

Given that

$\left[\begin{array}{ccccccccc}Letters&10&2&[\ ]&7&1&500&[\ ] \\Cost&0.45&0.90&6.75&[\ ]&[\ ]&[\ ] & 18.90\end{array}\right]$

Let:

<em /> $L \to$ <em> Letters</em>

<em /> $C \to$ <em> Cost</em>

<em />

Using proportional reasoning, we have:

$C = kL$

Where

<em /> $k \to$ <em> ratio of proportion</em>

For the first values of C and L, we have:

$C = kL$

$0.45 = k \times 10$

Divide both sides by 10

$k = 0.045$

So, the equation of proportion is:

$C = 0.045L$

<u>When C = 6.75, we have:</u>

$C = 0.045L$

$6.75 = 0.045L$

Solve for L

$L = \frac{6.75}{0.045}$

$L = 150$

<u>When L = 7, we have:</u>

$C = 0.045L$

$C = 0.045 \times 7$

$C = 0.315$

<u>When L = 1, we have:</u>

$C = 0.045L$

$C = 0.045 \times 1$

$C = 0.045$

<u>When L = 500, we have:</u>

$C =0.045L\\$

$C =0.045 \times 500$

$C =22.5$

<u>When C = 18.90, we have:</u>

$C = 0.045L$

$18.90 = 0.045L$

Solve for L

$L=\frac{18.90}{0.045}$

$L=420$

Hence, the complete table is:

$\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]$

Read more about proportions at:

brainly.com/question/21126582

8 0

2 years ago

MARKING BRAINLIEST AND +50 PTS IF CORRECT!!!!

Sphinxa [80]

Answer:If you have two parallel lines and shift both to the left by the same amount, that does not alter the distance between the lines. Thus, c is correct.

Step-by-step explanation:

4 0

3 years ago