Answer:
x = 16
Step-by-step explanation:
(whole secant) x (external part) = (tangent)^2
(x+2) * 2 = 6^2
2(x+2) = 36
Divide each side by 2
x+2 = 18
Subtract 2
x+2-2 = 18-2
x = 16
1) 2x + 9 = 2x -5
9 ≠ -5 ; No solution
2) 2x- 1 = x + 3
x = 4; One solution x = 4
3) x + 2 = x + 2
0 = 0; Identity (or all real numbers)
Answer:
We are given that triangle PQR is an isosceles triangle in which PQ = PR .
Since the base angles of an isosceles triangle are equal,
angle PQR = angle PRQ
Also, And we are given that
angle MRQ = angle NQR
In ΔQNR and ΔRMQ
∠NQR=∠MRQ (given)
QR = QR (common)
-triangles QNR is congruent to triangles RMQ - ASA - angle side angle
Ratio of the sides of the similar triangles are equal ,
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