Question

What is the area of a rectangle with vertices (Negative 8, Negative 2), (Negative 3, Negative 2), (Negative 3, Negative 6), and (Negative 8, Negative 6)?

Answer 1

Answer:

20 unit square is the area of a rectangle with given vertices.

Step-by-step explanation:

Area of the rectangle with vertices : Say ABCD:

$A(-8,-2), B(-3,-2), C (-3,-6), D(-8,-6)$

Distance formula : $(x_1,y_1) (x_2,y_2)$

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Length of the rectangle= AB

$AB=\sqrt{(-3-(-8))^2+(-2-(-2))^2}=5 units$

Breadth of the rectangle= BC

$BC=\sqrt{(-3-(-3))^2+(-6-(-2))^2}=4 units$

Area of rectangle = Length × Breadth = AB × BC

$A= 5 units \times 4 units = 20 unit^2$

20 unit square is the area of a rectangle with given vertices.

Answer 2

Answer:

20 square ft

Step-by-step explanation:

took the unit test