All categories

2 years ago

Help please!!! I really don’t know how to do this!

Mathematics

1 answer:

AysviL [449]2 years ago

5 0

Answer:

I'm going to do 1 as an example and using what I've taught you, you have to do the rest. Hope my explanation helps.

Step-by-step explanation:

We are given the points (-2, -4) and (-1, -1)

We need to find the slope.

The equation to do so is y2 - y1 / x2 - x1

lest say:

-2 is x1

-4 is y1

-1 is x2

-1 is y2

-1 - (-4) / -1 - (-2)

3/1 = 3

slope (m) = 3

We already know the y-intercept is 2

The equation of a line is y = mx + b

For this problem we just have to substitute what we already know.

y = (slope)x + y-intercept

y = 3x + 2

*TIP*

If the y-intercept is negative, let's say: b = -5 (using slope 8)

the equation will be y = 8x - 5

Hope this helps. I wish you all the best. :)

You might be interested in

I need help y’all, PLS HELP ME!

kondaur [170]

What is the question?

5 0

3 years ago

Read 2 more answers

Suze wants to make 5 pies for a party. She needs 1 1/2 cup of confectioners sugar for each pie. She has two bags of confectioner

Lunna [17]

Answer:

1 7/8 cups leftover

Step-by-step explanation:

The total amt. of sugar Suze needs is 5(1 1/2 cups) = 15/2 cups, or 7.5 cups.

Combining the 3 1/4 and 6 1/8 cups of sugar remaining in the bag results in 3 2/8 + 6 1/8 cups, or 9 3/8 cups total. She needs only 7.5 cups of this sugar.

Thus, she has leftover the following amount: 9 3/8 - 7 4/8 cups, which

simplifies to 1 7/8 cups

5 0

3 years ago

Read 2 more answers

Suppose you invest $2000 at annual interest rate of 4.5 % How much money do you have in the account after five years?

nataly862011 [7]

Answer:

Please check the explanation.

Step-by-step explanation:

To find the amount we use the formula:

$A=P\cdot \left(1+\frac{r}{n}\right)^{nt}$

Here:

A = total amount

P = principal or amount of money deposited,

r = annual interest rate

n = number of times compounded per year

t = time in years

Given

P=$2000

r=4.5%

n=4

t = 5 years

Calculating compounded quarterly 

After plugging in the values

$A=2000\left(1+\frac{4.5\%\:}{4}\right)^{4\cdot \:5}$

$A=2000\left(1+\frac{0.045}{4}\right)^{4\cdot \:5}$

$A=2000\cdot \frac{4.045^{20}}{4^{20}}$

$A=\frac{125\cdot \:4.045^{20}}{2^{36}}$

$A = 2,501.50$

Thus, If you deposit $2000 into an account paying 4.5% annual interest compounded quarterly, you will have $2501.50 after five years.

Calculating compounded semi-annually

n = 2

$A=2000\left(1+\frac{4.5\%\:}{2}\right)^{2\cdot \:5}$

$A=2000\left(1+\frac{0.045}{2}\right)^{2\cdot \:5}$

$A=2000\cdot \frac{2.045^{10}}{2^{10}}$

$A = 2,498.41$

Thus, If you deposit $2000 into an account paying 4.5% annual interest compounded semi-annually, you will have $2,498.41 after five years.

5 0

3 years ago

Hey! please help posted picture of question

lara31 [8.8K]

The answer is D) 2

Since it is given that there have been 9 slices eaten, we can assume that whatever amount of slices were cut in total will have 9 reduced from the amount. With the fraction 2/11, we know 11-9=2, which fits perfectly into this description so 2 slices have not been eaten.

3 0

3 years ago

Read 2 more answers

A courier service company wishes to estimate the proportion of people in various states that will use its services. Suppose the

Rasek [7]

Answer:

$\mu_{p} = p = 0.06$

And the standard error is given by:

$SE_{p} = \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$SE_[p]= \sqrt{\frac{0.06*(1-0.06)}{373}}= 0.0123$

And we want to find this probability:

$P(\hat p < 0.03)$

We can calculate the z score for this case and we got:

$z = \frac{\hat p -\mu_p}{\Se_p} = \frac{0.03-0.06}{0.0123}= -2.440$

And using the normal distribution table or excel we got:

$P(\hat p < 0.03)= P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

For this case we can find the mean and standard error for the sample proportion with these formulas:

$\mu_{p} = p = 0.06$

And the standard error is given by:

$SE_{p} = \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$SE_[p]= \sqrt{\frac{0.06*(1-0.06)}{373}}= 0.0123$

And we want to find this probability:

$P(\hat p < 0.03)$

We can calculate the z score for this case and we got:

$z = \frac{\hat p -\mu_p}{\SE_p} = \frac{0.03-0.06}{0.0123}= -2.440$

And using the normal distribution table or excel we got:

$P(\hat p < 0.03)= P(Z$

8 0

4 years ago