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2 years ago

Help please!!! I really don’t know how to do this!

Mathematics

1 answer:

AysviL [449]2 years ago

5 0

Answer:

I'm going to do 1 as an example and using what I've taught you, you have to do the rest. Hope my explanation helps.

Step-by-step explanation:

We are given the points (-2, -4) and (-1, -1)

We need to find the slope.

The equation to do so is y2 - y1 / x2 - x1

lest say:

-2 is x1

-4 is y1

-1 is x2

-1 is y2

-1 - (-4) / -1 - (-2)

3/1 = 3

slope (m) = 3

We already know the y-intercept is 2

The equation of a line is y = mx + b

For this problem we just have to substitute what we already know.

y = (slope)x + y-intercept

y = 3x + 2

*TIP*

If the y-intercept is negative, let's say: b = -5 (using slope 8)

the equation will be y = 8x - 5

Hope this helps. I wish you all the best. :)

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If 9a+6b+4c=7, what is -24b-16c-36a

zheka24 [161]

Rearrange the 2nd equation

-36a-24b-16c

divide the whole thing by 4 and you'll get
-9a-6b-4c

you'll realize it looks the same as your first equation except that all the + has become minus so the answer will be -7 instead for your new equation
-9a-6b-4c=-7

multiply the whole thing by 4 and you'll get
-36a-24b-16c = -28

so the answer you want is -28

6 0

3 years ago

Explain how to use the discriminant to determine the number and type of roots of a quadratic equation.

baherus [9]

The general form of the quadratic equation is :

$ax^2+bx+c=0$

The discriminant is :

$D=b^2-4\cdot a\cdot c$

And the general solution is :

$x=\frac{-b\pm\sqrt[]{D}}{2\cdot a}$

So, there are 3 situations for D

1. D = 0

So, the roots of a quadratic equation are two similar roots

2. D > 0

so, roots of a quadratic equation are two different roots

3. D < 0

so, roots of a quadratic equation are not real, two comlex roots

8 0

1 year ago

Mean = 5 13+14+15+19+19 =

Gelneren [198K]

Answer:

14.167

Step-by-step explanation:

assuming you meant 5+13

7 0

2 years ago

What effect does decreasing the temperature of a room have on a lifespan of a battery?

Leni [432]

This question is incomplete. There are options in the question (from reference) and no highlight in the red bolded text in the question.

What effect does decreasing the temperature of a room have on a lifespan of a battery?

Which variable is highlighted in red, bolded tex?

a . Independent

b . Dependent

c . Control

d . None

But the answer to both the independent and dependent variables will be provided and explained in detail.

Answer:

Independent variable: decrease in temperature

Dependent variable: lifespan of battery

Step-by-step explanation:

The independent variable in an experiment is defined as the variable that can be changed or manipulated in order to find an outcome while the dependent variable is defined as the variable that is influenced by the changes in the independent variable.

In the given example, a decrease in temperature is the dependent variable as it is changing and the lifespan of battery is the dependent variable as it is responding to the independent variable ?9decrease in temperature).

8 0

3 years ago

Two chemicals A and B are combined to form a chemical C. The rate, or velocity, of the reaction is proportional to the product o

Keith_Richards [23]

Answer:

32.1 g

Step-by-step explanation:

In each 3 grams of C, there are 2 grams of A and 1 gram of B. So, for some amount C, the amount remaining of A is 40 -(2C/3), and the amount remaining of B is (50 -C/3). Since the reaction rate is proportional to the product of these amounts, we have ...

C' = k(40 -2C/3)(50 -C/3) = (2k/9)(60 -C)(150 -C) . . . for some constant k

This is separable differential equation with a solution of the form ...

ln((150 -C)/(60 -C)) = at + b

We know that C(0) = 0, so b=ln(150/60) = ln(2.5). And we know that C(10) = 20, so ln(130/40) = 10a +ln(2.5) ⇒ a = ln(1.3)/10

Then our equation for C is ...

ln((150 -C)/(60 -C)) = t·ln(1.3)/10 +ln(2.5)

For t=20, this is ...

ln((150 -C)/(60 -C)) = 2ln(1.3) +ln(2.5) = ln(2.5·1.3²) = ln(4.225)

Taking antilogs, we have ...

(150 -C)/(60 -C) = 4.225

1 +90/(60 -C) = 4.225

C = 60 -90/3.225 ≈ 32.093 . . . . . grams of product in 20 minutes

In 20 minutes, about 32.1 grams of C are formed.

7 0

3 years ago