Answer:
t =1.453 decades from 1980 i.e in year 1994.5
Step-by-step explanation:
Given:
- Population @ year 1980 P = 678.97 thousands.
- Population @ year 2000 P = 776.73 thousands.
- The rate of increase is linear - constant rate.
Find:
As the population of San Francisco was revitalizing, for what value of the independent variable t did it reach 750 thousand ?
Solution:
- Develop an expression of population P as a function of time t in decades elapsed from year 1980 on-wards
- The linear expression can take a form of :
P(t) = m*t + C
- Where, m is the rate of increase.
C is the initial population.
- Formulate m:
m = (776.73 - 678.97) / 2 = 48.88
- Formulate C:
C = P (@ 1980) = 678.97
- Evaluate P(t) = 750:
P(t) = 48.8*t + 678.97
750 = 48.8*t + 678.97
t = 71.03/48.8
t =1.453 decades
Answer:
Step-by-step explanation:
we have
Solve for p
That means ----> Isolate the variable p
Multiply by q both sides
Simplify right side
Rewrite
47/12+23/6+7/2+5=47/12+46/12+42/12+60/12=195/12=16.25 gallons. The pool will be filled
I would either graph these (which would be a easiest) then you would see a line that goes through (0, -2) on the y-axis
And you can either determine the slope from the graph or pick two points above and find the slope.
or spread them out evenly and fill out the missing pieces.
-8. -4
-4. -3
0
4. -1
6. -0.5
8
12. 1
Fill in the middle values and you can put (6,-0.5) on there
What pattern do u see? This way would be pretty hard.
Equation: y=(1/4)x-2
