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2 years ago

Please help me with this - its about percent changes

Mathematics

1 answer:

Serhud [2]2 years ago

6 0

Answer:

110.06

Step-by-step explanation:

Make a ratio: 95.20 / x = 86.5 / 100 (86.5 = 100% - 13.5%)

Cross multiply: 95.20 x 100 = 86.5x

9520 = 86.5x

110.06 = x

You might be interested in

you invested $1,900 at a 4% interest compounded annually for 3 years.how much interest did you earn in 3 years

zzz [600]

Answer:

The amount is $2137.24 and the interest is $237.24.

Step-by-step explanation:

STEP 1: To find amount we use formula:

A = P $(1+\frac{x}{y} )nt$

A = total amount P = principal or amount of money deposited, r = annual interest rate n

= number of times compounded per year t = time in years In this example we have

P = $1900 , r = 4% , n = 1 and t = 3 years

After plugging the given information we have

A = 1900 $(1+\frac{0.04}{1})^{1*3}$

A = 1900 · 1.0 $4^{3}$

A = 1900 · 1.124864

A = 2137.24

STEP 2: To find interest we use formula A = P + I, since A = $2137.24 and P = $1900 we

have:

A = P + I

2137.24 = 1900 + I

I = 2137.24 − 1900

I = 237.24

7 0

3 years ago

A population of 6000 animals decrease at an annual rate of 0.7%. What is the expected population in 12 years? Round your answer

solmaris [256]

Answer:

The population is expected to be 5515 animals in 12 years.

Step-by-step explanation:

This problem can be solved by using a compounded interest formula with a negative interest rate, since the number of animals are decreasing. We have:

final population = initial population * (1 - r)^(t)

Where r is rate of decline and t is the time elapsed. Applying the data from the question we have:

final population = 6000*(1 - 0.007)^(12)

final population = 6000*(0.993)^12 = 5514.9582 animals

The population is expected to be 5515 animals in 12 years.

6 0

4 years ago

10 and<br> In acute triangle ABC, side b = 12, side c =<br> mLA = 42. Find side a.

Slav-nsk [51]

Answer:

Step-by-step explanation:

I'm not completely sure, however.

12+10 = 22

42-22 = 20

6 0

3 years ago

Mike is c years old, he is half as old as Steve. How old was Steve two years ago?

vredina [299]

Answer:

2(c-1)

Step-by-step explanation:

MIke is c

Steve is 2c

Steve was 2c -2 two years ago

5 0

2 years ago

Candy. Someone hands you a box of a dozen chocolate-covered candies, telling you that half are vanilla creams and the other half

BaLLatris [955]

Answer:

a) P=0.091

b) If there are half of each taste, picking 3 vainilla in a row has a rather improbable chance (9%), but it is still possible that there are 6 of each taste.

c) The probability of picking 4 vainilla in a row, if there are half of each taste, is P=0.030.

This is a very improbable case, so if this happens we would have reasons to think that there are more than half vainilla candies in the box.

Step-by-step explanation:

We can model this problem with the variable x: number of picked vainilla in a row, following a hypergeometric distribution:

$P(x=k)=\dfrac{\binom{K}{k}\cdot \binom{N-K}{n-k}}{\binom{N}{n}}$

being:

N is the population size (12 candies),

K is the number of success states in the population (6 vainilla candies),

n is the number of draws (3 in point a, 4 in point c),

k is the number of observed successes (3 in point a, 4 in point c),

a) We can calculate this as:

$P(x=3)=\dfrac{\binom{6}{3}\cdot \binom{12-6}{3-3}}{\binom{12}{3}}=\dfrac{\binom{6}{3}\cdot \binom{6}{0}}{\binom{12}{3}}=\dfrac{20\cdot 1}{220}=0.091$

b) If there are half of each taste, picking 3 vainilla in a row has a rather improbable chance (9%), but is possible.

c) In the case k=4, we have:

$P(x=3)=\dfrac{\binom{6}{4}\cdot \binom{6}{0}}{\binom{12}{4}}=\dfrac{15\cdot 1}{495}=0.030$

This is a very improbable case, so we would have reasons to think that there are more than half vainilla candies in the box.

4 0

3 years ago