Question

What is the equation in slope-intercept form of a line that is perpendicular to y=13x+2 and passes through the point (3, 1)? Enter your answer by filling in the boxes. y = x +
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Answer 1

Answer:

y = -1/13x + 1 3/13

Step-by-step explanation:

y = 13x + 2

Perpendicular

y = -1/13x + b

Finding b:

1 = -1/13 * 3 + b

1 = -3/13 + b

1 3/13 = b

y = -1/13x + 1 3/13

Please let me know if I'm wrong :)

Answer 2

The answer is y=-3x+10