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kakasveta [241]

3 years ago

14

What is the equation in slope-intercept form of a line that is perpendicular to y=13x+2 and passes through the point (3, 1)? Ent

er your answer by filling in the boxes. y = x +
plz be speed ill give brainliest

2 answers:

geniusboy [140]3 years ago

8 0

Answer:

y = -1/13x + 1 3/13

Step-by-step explanation:

y = 13x + 2

Perpendicular

y = -1/13x + b

Finding b:

1 = -1/13 * 3 + b

1 = -3/13 + b

1 3/13 = b

y = -1/13x + 1 3/13

Please let me know if I'm wrong :)

o-na [289]3 years ago

8 0

The answer is y=-3x+10

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NO LINKS!!! PLS HELP ME IM TRYING TO GRADUATE PLSSS !!! Find the midpoint of the segment below and enter its coordinates as an

Leto [7]

Answer:

x = 5/2 , y = -7/2

Step-by-step explanation:

<em>r's</em><em> your</em><em> solution</em>

<em> </em><em> </em><em>=</em><em>></em><em> </em><em>formula</em><em> </em><em>for</em><em> </em><em>finding</em><em> </em><em>midpoint</em><em> </em><em>=</em><em>.</em><em>(</em><em> </em><em>X1</em><em> </em><em>+</em><em> </em><em>X</em><em>2/</em><em>)</em><em>/</em><em>2</em><em> </em><em>,</em><em> </em><em>(</em><em>Y1+</em><em>Y2)</em><em>/</em><em>2</em>

<em>=</em><em>></em><em> </em><em>putting</em><em> </em><em>the </em><em>value</em><em> </em><em>of </em><em>in </em><em>formula</em>

<em> </em><em> </em><em>=</em><em>></em><em> </em><em>x=</em><em> </em><em> </em><em>4</em><em>+</em><em>1</em><em>/</em><em>2</em><em> </em><em>,</em><em> </em><em>y </em><em>=</em><em> </em><em>-</em><em>1</em><em>-</em><em>6</em><em>/</em><em>2</em>

<em>=</em><em>></em><em> </em><em>x </em><em>=</em><em> </em><em>5</em><em>/</em><em>2</em><em> </em><em>,</em><em> </em><em>y </em><em>=</em><em> </em><em>-</em><em>7</em><em>/</em><em>2</em>

<em>hope</em><em> it</em><em> helps</em>

3 0

3 years ago

1. What is the value of the y variable in the solution to the following system of equations?

ollegr [7]

Part 1)

we have

$3x-6y=3$ ------> equation A

$7x-5y=-11$ ------> equation B

Multiply by $-7$ the equation A

$-7(3x-6y)=-7*3$

$-21x+42y=-21$ ------> equation C

Multiply by $3$ the equation B

$3*(7x-5y)=-11*3$

$21x-15y=-33$ -------> equation D

Adds equation C and equation D

$-21x+42y=-21 \\21x-15y=-33\\---------- \\ 42y-15y=-21-33\\27y=-54 \\ y=-2$

therefore

<u>the answer Part 1) is the option A </u>

$y=-2$

Part 2)

we have

$3x+y=6$

$y=-3x+6$ ------> equation A

$6x+2y=8$

Simplify Divide by $2$ both sides

$3x+y=4$

$y=-3x+4$ ------> equation B

the lines A and B are parallel lines, because the slope m is equal

so

The system has no solution

therefore

<u>the answer Part 2) is the option D</u>

There is no x value as there is no solution to the system.

Part 3)

we have

$4x+2y=6$ ------> equation A

$x-y=3$

$y=x-3$ ------> equation B

substitute equation B in equation A

$4x+2[x-3]=6$

$6x-6=6$

$6x=12$

$x=2$

therefore

<u>the answer part 3) is the option D</u>

$x=2$

Part 4)

Let

x---------> The number of one-step equations

y---------> The number of two-step equations

we know that

$x+y=1,120$

$x=1,120-y$ -------> equation A

$3x-2y=1,300$ ------> equation B

substitute equation A in equation B

$3[1,120-y]-2y=1,300$

$3,360-5y=1,300$

$5y=3,360-1,300$

$5y=2,060$

$y=412$

therefore

<u>the answer part 4) is the option D</u>

$y=412$

8 0

2 years ago

Read 2 more answers

Find the expression you can substitute for 5x+y=10

Gennadij [26K]

5x=5*2
Y=0 so 5*2=10 +0 =10

7 0

3 years ago

Sine, cosines and tangent of 30 45 and 60 degrees

bonufazy [111]

Answer:

Sine 30 =

$\frac{1}{2}$

Sine 45 =

$\sqrt{ \frac{2}{2} }$

Sine 60 =

$\sqrt{ \frac{3}{2} }$

Cos 30 =

$\sqrt{ \frac{3}{2} }$

Cos 45 =

$\sqrt{ \frac{2}{2} }$

Cos 60 =

$\frac{1}{2}$

Tan 30 =

$\sqrt{ \frac{3}{3} }$

Tan 45 =

$1$

Tan 60 =

$\sqrt{3}$

Step-by-step explanation:

I hope it helps

3 0

3 years ago

Find the 6th term of the arthemetic sequence 2x+3,-2x+10,-6x+17,..

sveticcg [70]

Answer:4h term: -10x+24, 5th term: -14x+31, 6th term: -18x+ 38

Step-by-step explanation:

8 0

2 years ago