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VashaNatasha [74]
3 years ago
13

PLS HELP ME I'M SO CONFUSED!!!!!!

Mathematics
2 answers:
LenKa [72]3 years ago
5 0

Answer:

  • a = -3, b = 2.5, c = - 1/2

Step-by-step explanation:

1)

  • 3^a=1/27
  • 3^a=1/3^3
  • 3^a=3^{-3}
  • a=-3

2)

  • 3^b=9\sqrt{3}
  • 3^b=3^2*3^{1/2}
  • 3^b=3^{2+1/2}
  • 3^b=3^{2.5}
  • b=2.5

3)

  • 3^c=1/\sqrt{3}
  • 3^c=1/3^{1/2}
  • 3^c=3^{-1/2}
  • c = - 1/2

WARRIOR [948]3 years ago
3 0

Step-by-step explanation:

You have to use logarithms.

1) a = log_3 (1/27) = -log_3 (27) = -3

2) b = log_3 (9 * 3^(1/2)) = log_3 (3 ^ {5/2}) = 5/2

3) c = -log_3 (sqrt3) = -1/2

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5 0
3 years ago
Name the property of real numbers illustrated by the equation. π + 10 = 10 + π
Dovator [93]
This is the commutative property (of addition, but this applies to multiplication as well)It doesn't matter which order the numbers are added in, the same result will be achieved.1+2 = 2+12*4 = 4*2


6 0
4 years ago
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What are the period and phase shift for f(x) = 3 tan(4x + π)?
Y_Kistochka [10]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\

\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{  A}}|\\\\
\bullet \textit{ horizontal or "phase" shift by }\frac{{{  C}}}{{{  B}}}\\
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\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period}\\
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\bf \begin{array}{lllllll}
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7 0
3 years ago
Guido is a citizen and resident of Belgium. He has a full-time job in Belgium and has lived there with his family for the past 1
Korvikt [17]

Answer:

<em>Guido stayed in US in 2018 for 180 days which are greater than 31 days. </em>

<em>Guido Stayed in US in 2018 and in 2017 = (180 + 66) > 183 days. </em>

<em>So, yes Guido does meet US Statutory definition in 2018 and stayed 180 days in 2018.</em>  

Step-by-step explanation:

Let's find out how many days in total Guido stayed in US in these 3 years 2017, 2018 and 2019.

Year = 2017

Days = 200

Year = 2018

Days = 180

Year = 2019

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In U.S, there are two tests are in place and for non-citizen of U.S and for the resident Alien or non - resident Alien status, one must pass one of these two tests, which are as follows:

1. Green Card Test:

2. Substantial Presence Test:

Here, in this problem, Guido is citizen and resident of Belgium. So, will check his criteria according to the substantial presence test.

So, the question is: how many days Guido was present in the U.S in 2018 under resident alien status.

In 2018, Guido stayed in US for 180 days.

So, according to the Substantial Presence test, one must be physically present in US for more than 31 days to be eligible for resident alien status. In addition, in 2018, his total of physical presence in US in 2018 and one third of physical presence in 2017 must be greater than 183 days.

If we see, both conditions are matched in case of Guido.

<em>Guido stayed in US in 2018 for 180 days which are greater than 31 days. </em>

<em>Guido Stayed in US in 2018 and in 2017 = (180 + 66) > 183 days. </em>

<em>So, yes Guido does meet US Statutory definition in 2018 and stayed 180 days in 2018.</em>  

3 0
3 years ago
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FinnZ [79.3K]

Answer: y= -1

Step-by-step explanation:

Add 5 to both sides,

y-5+5=-9y-15+5

Simplify,

y=-9y-10

Add 9y to both sides,

y+9y=-9y-10+9y

Simplify,

10y=-10

Divide both sides by ten.

10y over 10 = -10 over 10

There you go!

7 0
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