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2 years ago

Anyone know the answer ?

Mathematics

2 answers:

Firdavs [7]2 years ago

8 0

Answer:

Step-by-step explanation:

10x-2=9x+5 because the angles are the same as m and n are parallel.

10x=9x+7

x=7

Aleksandr-060686 [28]2 years ago

5 0

I mean i can help! So start off by solving (10x-2)°= (5x - 1) next, solve (9x+5)°= the same because there is no solution, add (5x - 1)+(9x+5)= 2(7x +2) i hope this answers your question!

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A school bought pens, each costing $1, and pencils, each costing $0.5. The cost of the whole purchase was $220. How many pens an

Mkey [24]

Answer:

120 pens and 200 pencils.

Explanation:

You can set a system of two equations.

1. Variables

x: number of pens
y: number of pencils

2. Cost

each pen costs $1, then x pens costs: x
each pencil costs $0.5, then y pencil costs: 0.5y

Then, the total cost is: x + 0.5y

The cost of the whole purchase was $ 220, then the first equation is:

x + 0.5y = 220 ↔ equation (1)

3. There were 80 more pencils than pens

Then:

pencils = 80 + pens

↓ ↓

y = 80 + x ↔ equation (2)

4. Solve the system

i) Substitute the equation (2) into the equation (1):

x + 0.5(80 + x) = 220

ii) Solve

x + 40 + 0.5x = 220

1.5x = 180

x = 180/1.5

x = 120 pens

iii) Substitute x = 120 into the equation (2)

y = 80 + 120

y = 200 pencils

Solution: 120 pens and 200 pencils ← answer

6 0

2 years ago

Content://media/external/file/8717

Alja [10]

Bro what is the question

4 0

3 years ago

Read 2 more answers

Find the polynomial of minimum degree, with real coefficients, zeros at

drek231 [11]

Answer:

$\huge\boxed{p(x)=4x^3-20x^2+4x+300}$

Step-by-step explanation:

$\text{If}\ x=4\pm3i\ \text{and}\ x=-3\ \text{are the zeros of a polynomial, then it has a form:}\\\\p(x)=\bigg(x-(4-3i)\bigg)\bigg(x-(4+3i)\bigg)\bigg(x-(-3)\bigg)\bigg(r(x)\bigg)\\\\p(x)=(x-4+3i)(x-4-3i)(x+3)\bigg(r(x)\bigg)\\\\p(x)=\underbrace{\bigg((x-4)+3i\bigg)\bigg((x-4)-3i\bigg)}_{\text{use}\ (a+b)(a-b)=a^2-b^2}(x+3)\bigg(r(x)\bigg)\\\\p(x)=\bigg((x-4)^2-(3i)^2\bigg)(x+3)\bigg(r(x)\bigg)\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2$

$p(x)=(x^2-2(x)(4)+4^2-3^2i^2)(x+3)\bigg(r(x)\bigg)\qquad\text{use}\ i^2=-1\\\\p(x)=(x^2-8x+16-9(-1))(x+3)\bigg(r(x)\bigg)\\\\p(x)=(x^2-8x+16+9)(x+3)\bigg(r(x)\bigg)\\\\p(x)=(x^2-8x+25)(x+3)\bigg(r(x)\bigg)\qquad\text{use FOIL}:\ (a+b)(c+d)=ac+ad+bc+bd\\\\p(x)=\bigg((x^2)(x)+(x^2)(3)+(-8x)(x)+(-8x)(3)+(25)(x)+(25)(3)\bigg)\bigg(r(x)\bigg)\\\\p(x)=(x^3+3x^2-8x^2-24x+25x+75)\bigg(r(x)\bigg)\qquad\text{combine like terms}\\\\p(x)=(x^3-5x^2+x+75)\bigg(r(x)\bigg)$

$\text{The y-intercept is at 300}.\\\\\text{For}\ w(x)=a_nx^n+a_{n-1}x^{n-1}+a_{n-2}x^{n-2}+...+a_1x+a_0\\\\\text{y-intercept is}\ a_0\\\\\text{Therefore for}\ p(x)=(x^3-5x^2+x+75)\bigg(r(x)\bigg)\\\\\text{y-intercet is}\ 75\bigg(r(x)\bigg)\\\\75\bigg(r(x)\bigg)=300\qquad\text{divide both sides by 75}\\\\r(x)=4\\\\\text{Finally:}\\\\p(x)=(x^3-5x^2+x+75)(4)\qquad\text{use the distributive property}\\\\p(x)=(x^3)(4)+(-5x^2)(4)+(x)(4)+(75)(4)\\\\p(x)=4x^3-20x^2+4x+300$

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3 years ago

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Mars2501 [29]

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