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ASHA 777 [7]
3 years ago
8

Help please it’s worth 20 points

Chemistry
2 answers:
spayn [35]3 years ago
5 0

Answer:

it has increased by 3 or 4 times more then the last 5 decades.

Explanation:

research purposes.

torisob [31]3 years ago
3 0

Answer:

pls mark me as brainliest

Explanation:

A disaster related to a weather, climate or water hazard occurred every day on average over the past 50 years – killing 115 people and causing US$ 202 million in losses daily, according to a comprehensive new report from the World Meteorological Organization (WMO).

The number of disasters has increased by a factor of five over the 50-year period, driven by climate change, more extreme weather and improved reporting. But, thanks to improved early warnings and disaster management, the number of deaths decreased almost three-fold.

According to the WMO Atlas of Mortality and Economic Losses from Weather, Climate and Water Extremes (1970 – 2019), there were more than 11 000 reported disasters attributed to these hazards globally, with just over 2 million deaths and US$ 3.64 trillion in losses.

The report is the most comprehensive review of mortality and economic losses from weather, water and climate extremes to date. It assesses the entire 50-year period as well as by individual decade.

From 1970 to 2019, weather, climate and water hazards accounted for 50% of all disasters, 45% of all reported deaths and 74% of all reported economic losses.

More than 91% of these deaths occurred in developing countries (using the United Nations Country Classification).

Of the top 10 disasters, the hazards that led to the largest human losses during the period have been droughts (650 000 deaths), storms (577 232 deaths), floods (58 700 deaths) and extreme temperature (55 736 deaths).

Deaths decreased almost threefold from 1970 to 2019. Death tolls fell from over 50 000 deaths in the 1970s to less than 20 000 in the 2010s. The 1970s and 1980s reported an average of 170 related deaths per day. In the 1990s, that average fell by one third to 90 related deaths per day, then continued to fall in the 2010s to 40 related deaths per day.

With regard to economic losses, the top 10 events include storms (US$ 521 billion) and floods (US$ 115 billion).

During the 50-year period, US$ 202 million dollars in damage occurred on average every day. Economic losses have increased sevenfold from the 1970s to the 2010s. The reported losses from 2010–2019 (US$ 383 million per day on average over the decade) were seven times the amount reported from 1970–1979 (US$ 49 million). Storms were the most prevalent cause of damage, resulting in the largest economic losses around the globe. It is the sole hazard for which the attributed portion is continually increasing.

Three of the costliest 10 disasters occurred in 2017: Hurricanes Harvey (US$ 96.9 billion), Maria (US$ 69.4 billion) and Irma (US$ 58.2 billion).  These three hurricanes alone accounted for 35% of the total economic losses of the top 10 disasters around the world from 1970 to 2019.

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Hydrogen gas (a potential future fuel) can be formed by the reaction of methane with water according to the following equation:
dem82 [27]

Answer:

The percent yield of the reaction is 62.05 %

Explanation:

Step 1: Data given

Volume of methane = 25.5 L

Pressure of methane = 732 torr

Temperature = 25.0 °C = 298 K

Volume of water vapor = 22.0 L

Pressure of H2O = 704 torr

Temperature = 125 °C

The reaction produces 26.0 L of hydrogen gas measured at STP

Step 2: The balanced equation

CH4(g) + H2O(g) → CO(g) + 3H2(g)

Step 3: Calculate moles methane

p*V = n*R*T

⇒with p = the pressure of methane = 0.963158 atm

⇒with V = the volume of methane = 25.5 L

⇒with n = the moles of methane = TO BE DETERMINED

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 298 K

n = (p*V) / (R*T)

n = (0.963158 * 25.5 ) / ( 0.08206 * 298)

n = 1.0044 moles

Step 4: Calculate moles H2O

p*V = n*R*T

⇒with p = the pressure of methane = 0.926316 atm

⇒with V = the volume of methane = 22.0 L

⇒with n = the moles of methane = TO BE DETERMINED

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 398 K

n = (p*V) / (R*T)

n = (0.926316 * 22.0) / (0.08206 * 398)

n = 0.624 moles

Step 5: Calculate the limiting reactant

For 1 mol methane we need 1 mol H2O to produce 1 mol CO and 3 moles H2

H2O is the limiting reactant. It will completely be consumed (0.624 moles).

Methane is in excess. There will react 0.624 moles. There will remain 1.0044 - 0.624 moles = 0.3804 moles methane

Step 6: Calculate moles hydrogen gas

For 1 mol methane we need 1 mol H2O to produce 1 mol CO and 3 moles H2

For 0.624 moles H2O we'll have 3*0.624 = 1.872 moles

Step 9: Calculate volume of H2 at STP

1.0 mol at STP has a volume of 22.4 L

1.872 moles has a volume of 1.872 * 22.4 = 41.9 L

Step 10: Calculate the percent yield of the reaction

% yield = (actual yield / theoretical yield) * 100 %

% yield = ( 26.0 L / 41.9 L) *100 %

% yield = 62.05 %

The percent yield of the reaction is 62.05 %

6 0
3 years ago
Read 2 more answers
Solution A has a pH of 3 and solution Z has
igor_vitrenko [27]
PH of a solution is -ln[H3O+] so,in case of A pH=3 or,-log[H3O+]=3 or,[H3O+]=10^-3 in case of B pH=6 pr,-log[H3O+]=6 or, [H3O+]=10^-6 so,hydronium ion concentration in solution A /the hydronium ion concentration in solution Z =10^-3/10^-6 =1000 2) Ca(OH)2+2 HNO3=Ca(NO3)2+2 H2O so the answer is 2.
5 0
4 years ago
Read 2 more answers
What is the Molar Mass of methylammonium bromide: Use the Periodic Table and round to the nearest hundredths.
egoroff_w [7]

The molar mass of methylammonium bromide is 111u.

<h3>What is molar mass?</h3>

The molar mass is defined as the mass per unit amount of substance of a given chemical entity.

Multiply the atomic weight (from the periodic table) of each element by the number of atoms of that element present in the compound.

Add it all together and put units of grams/mole after the number.

Atomic weight of H is 1u

Atomic weight of N is  14u

Atomic weight of C is  12u

Atomic weight of Br is  79u

Calculating molar mass of  2H_3NCH_3Br =2(1 x3+ 14+12+ 1 x 3 +79) = 111u

Hence, the molar mass of methylammonium bromide is 111u.

Learn more about molar mass here:

brainly.com/question/12127540

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8 0
2 years ago
What is its molar heat of vaporization in kilojoules per mole if its vapor pressure at 20°C is 11.0 torr?
NemiM [27]

Answer:

<em>H.vap = 6.544 kJ/mol</em>

Explanation:

Clausius-Clapeyron Equation

<em>In P = H.vap / RT</em> where T = 20 + 273 = 293K

H.vap = In P (RT) = In 11 (8.314 x 293) = 6543.861 J/mol = 6.544 kJ/mol

7 0
3 years ago
What is "Scarcity" <br><img src="https://tex.z-dn.net/?f=." id="TexFormula1" title="." alt="." align="absmiddle" class="latex-fo
Lana71 [14]

Explanation:

I don't know sorry ok I have some work so I m sorry

4 0
3 years ago
Read 2 more answers
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