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saul85 [17]
3 years ago
13

Simon has collected three samples from the coral reef where he observes marine life. He must determine whether each one is a pur

e substance or a mixture.
SAMPLE A : Clear liquid. Evaporates at 70*C. Appearance does not change.
SAMPLE B : Clear, blue liquid. Boils at 90*C leaving blue crystals behind. Appearance does not change.
SAMPLE C : Opaque, whitish liquid. Boils at 100*C leaving white crystals behind. Dust appears to settle at bottom.

Answer choices for each one are - homogeneous mixture, heterogeneous mixture, or pure substance
Chemistry
2 answers:
zysi [14]3 years ago
7 0
SAMPLE A - <span>pure substance.
</span>SAMPLE B - <span>homogeneous mixture.
</span>SAMPLE C - <span>heterogeneous mixture.
</span>Pure substance - <span>constant composition and properties.</span>
Homogeneous mixture - same uniform appearance and composition.
Heterogeneous mixture - <span>not </span>uniform<span> in composition, two phases (liquid and dust).
</span>
Marta_Voda [28]3 years ago
4 0

Answer: Sample A is a pure substance, Sample B  is a homogeneous mixture and Sample C is a heterogeneous mixture.

Explanation:

Homogeneous mixture : In these mixture, all the component are uniformly distributed throughout the mixture.For example: sugar-water solution.

Heterogeneous mixture : In these mixture, all the component are not uniformly distributed throughout the mixture.For example: sand-water solution.

Pure substance : These are the substance made up only one type of atom or molecule.They have fixed value of boiling and melting points. For example: diamond, pure sugar etc.

Sample A is a clear liquid which evaporates at 70^oC with no change in appearance. Hence, pure substance.

Sample B is a clear blue liquid which boils at 90^oC and leaves blue crystals behind with change in appearance. Hence, homogeneous mixture

Sample C is a opaque, whitish liquid which boils at 100^oC and leaves white crystals behind with dust particles settled in the bottom. Hence, heterogeneous mixture.

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Explanation:

When the student mixed the solution sodium carbonate with solution of copper(II) sulfate ; Copper Hydroxocarbonate , sodium sulfate and carbon dioxide gas was obtained as a products.

The balanced chemical reaction

2Na_2CO_3+2CuSO_4\rightarrow Cu_2(OH)_2CO_3+2Na_2SO_4+CO_2

Where:

Cu_2(OH)_2CO_3 = Copper(II) Hydroxocarbonate

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3 years ago
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One
Balance the Equation.
This has been done for you or it is given. Anyway this step is finished, but it must always be done.

Two
Find the molar mass of C6H12O6
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Three
Find the mols of C6H12O6
n = ???
Molar Mass = 180 grams / mol
given mass = 13.2 grams.

n = given mass / molar mass
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n = 0.07333333 mols.

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1/0.073333 = 6/x Cross multiply
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R = 0.082057 
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T = 0 + 273 = 273
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1 * V = 0.43999 * 082057 * 273
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The answer is to this question is c
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Explanation:

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