Simon has collected three samples from the coral reef where he observes marine life. He must determine whether each one is a pur
2 answers:
Answer: Sample A is a pure substance, Sample B is a homogeneous mixture and Sample C is a heterogeneous mixture.
Explanation:
Homogeneous mixture : In these mixture, all the component are uniformly distributed throughout the mixture.For example: sugar-water solution.
Heterogeneous mixture : In these mixture, all the component are not uniformly distributed throughout the mixture.For example: sand-water solution.
Pure substance : These are the substance made up only one type of atom or molecule.They have fixed value of boiling and melting points. For example: diamond, pure sugar etc.
Sample A is a clear liquid which evaporates at with no change in appearance. Hence, pure substance.
Sample B is a clear blue liquid which boils at and leaves blue crystals behind with change in appearance. Hence, homogeneous mixture
Sample C is a opaque, whitish liquid which boils at and leaves white crystals behind with dust particles settled in the bottom. Hence, heterogeneous mixture.
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Answer:
<h2>91.2</h2>Explanation:
Given that:
Temperature = 60 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (60 + 273.15) K = 333.15 K
n = 5.14 × 10⁻³ mol
V = 1,171 mL = 1.171 L ( 1 mL = 0.001 L)
Using ideal gas equation as:
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 62.364 L Torr/ K mol
Applying the equation as:
P × 1.171 L = 5.14 × 10⁻³ mol × 62.364 L Torr/ K mol × 333.15 K
<u>⇒P = 91.2 torr</u>