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Karolina [17]
3 years ago
12

What is the value of y? Enter your answer in the box. y = __

Mathematics
2 answers:
IgorC [24]3 years ago
7 0

Answer:y=42

Step-by-step explanation:

Kamila [148]3 years ago
5 0

<u>Answer</u>:

y = 64°

<u>Explanation</u>:

total sum of interior angle of triangle is 180°

solving:

y + 79° + 37° = 180°

y + 116° = 180°

y = 180° - 116°

y = 64°

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If the scale on a map is inches/feet =2/10, how would the following lengths be represented?
Alex787 [66]
The answer is B 30 feet
7 0
3 years ago
What is the balance after 15 years in a savings account that earns 2% interest compounded bimonthly when the initial deposit is
Ierofanga [76]

Answer:

$1348.07

Step-by-step explanation:

Hello!

<h3>Compound Interest Formula: A = P(1 + \frac rn)^{nt}</h3>
  • A = Account Balance
  • P = Principle/Initial Amount
  • r = Rate of Interest (decimal)
  • n = Number of times compounded (per year)
  • t = Number of Years

<h3>Given Information</h3>
  • Account Balance = ?
  • Principle Amount = $1000
  • Rate of Interest = 0.02

Why is the Rate 0.02?

This is because we are gaining money, so the multiplier should be greater than 1. We already added 1, which is 100% so you simply add the 0.02 for the extra 2%.

  • Number of times compounded per year = 6

This is because it is being compounded bi-monthly, or once every 2 months. 12 months divided by 2 months is 6 months, so 6 times a year.

  • Number of years = 15

<h2>Solve </h2>

Solve by plugging in the given values into the formula.

  • A = P(1 + \frac rn)^{nt}
  • A = 1000(1 + \frac {0.02}{6})^{6*15}
  • A = 1000(1 + 0.00333...)^{90}
  • A = 1000(1.00333...)^{90}
  • A = 1000(1.145743)
  • A \approx 1457.43

This is really close to the first option, and since there is rounding involved with the repeating decimal, the first option should be correct.

The answer is $1348.07.

3 0
2 years ago
Csi geometry transformations answers
Vedmedyk [2.9K]
Yeah what is the question
4 0
4 years ago
For the inverse variation equation xy=k, what is the constant of variation,k, when x = -3and y=-2
const2013 [10]

Answer:

6

Step-by-step explanation:

xy=k

Value of k ; when ; x = - 3 and y = - 2

Put x = - 3 and y = - 2 into the equation :

(-3)(-2) = k

-3 * - 2 = k

6 = k

The constant of variation k = 6

8 0
3 years ago
Given a population with a mean of muμequals=100100 and a variance of sigma squaredσ2equals=3636​, the central limit theorem appl
lakkis [162]

Answer:

a) \bar X \sim N(100,\frac{6}{\sqrt{25}}=1.2)

\mu_{\bar X}=100 \sigma^2_{\bar X}=1

b) P(\bar X >101)=1-P(\bar X

c) P(\bar X

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".  

The complement rule is a theorem that provides a connection between the probability of an event and the probability of the complement of the event. Lat A the event of interest and A' the complement. The rule is defined by: P(A)+P(A') =1

Let X the random variable that represent the variable of interest on this case, and for this case we know the distribution for X is given by:  

X \sim N(\mu=100,\sigma=6)  

And let \bar X represent the sample mean, by the central limit theorem, the distribution for the sample mean is given by:  

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})  

a. What are the mean and variance of the sampling distribution for the sample​ means?

\bar X \sim N(100,\frac{6}{\sqrt{25}}=1.2)

\mu_{\bar X}=100 \sigma^2_{\bar X}=1.2^2=1.44

b. What is the probability that x overbarxgreater than>101

First we can to find the z score for the value of 101. And in order to do this we need to apply the formula for the z score given by:  

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}  

If we apply this formula to our probability we got this:  

z=\frac{101-100}{\frac{6}{\sqrt{25}}}=0.833  

And we want to find this probability:

P(\bar X >101)=1-P(\bar X

On this last step we use the complement rule.  

c. What is the probability that x bar 98less than

First we can to find the z score for the value of 98.

z=\frac{98-100}{\frac{6}{\sqrt{25}}}=-1.67  

And we want to find this probability:

P(\bar X

5 0
4 years ago
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