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3 years ago

Б) Which label on the cone below represents the radius? ОООО

Mathematics

1 answer:

lions [1.4K]3 years ago

6 0

The radius is found on the letter C!

I hope this helped! Mark me Brainliest! :) -Raven❤️

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Convert Y = -7/2x-11 to Standard Form

monitta

Answer:

7x + 2y = -22

Step-by-step explanation:

Standard form looks like Ax + By = C.

Start with Y = -7/2x-11. Better to write that as Y = (-7/2)x - 11 to emphasize that the coefficient of x is the fraction -7/2.

Move the (-7/2)x term to the left:

(7/2)x + y = -11

Multiply all terms by 2 to eliminate the fractions:

7x + 2y = -22 (answer)

6 0

3 years ago

The yearly sales of candles decreased from 560 to 476. By what percentage did the candle sales decrease?

Korvikt [17]

The candle sales decreases to - 15 percentage.

<u>Step-by-step explanation:</u>

(476 - 560) : 560 x 100

= (476 : 560 - 1)100

= 85 - 100 = - 15

Therefore, - 15% did the candle sales decrease.

4 0

3 years ago

Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour

UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

$C(t) = C(0)e^{rt}$

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So $C(0) = 110$

Husband

Half life of 4 hours. So

$C(4) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{4r}$

$e^{4r} = 0.5$

Applying ln to both sides

$\ln{e^{4r}} = \ln{0.5}$

$4r = \ln{0.5}$

$r = \frac{\ln{0.5}}{4}$

$r = -0.1733$

So for the husband

$C(t) = 110e^{-0.1733t}$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.1733t}$

$C(11) = 110e^{-0.1733*11} = 16.35$

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

$C(10) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{10}$

$e^{10r} = 0.5$

Applying ln to both sides

$\ln{e^{10r}} = \ln{0.5}$

$10r = \ln{0.5}$

$r = \frac{\ln{0.5}}{10}$

$r = -0.0693$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.0693t}$

$C(11) = 110e^{-0.0693*11} = 51.33$

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

7 0

3 years ago

A 27 foot plece of wire is connected

morpeh [17]

3 .......................

5 0

2 years ago

Round 6,261 to the nearest hundred

postnew [5]

Answer:

6300

Step-by-step explanation:

6261 to the nearest 100 -----261 would round up to 300 =6300

6 0

3 years ago