9 walleye should be put into the pool to model the conditions in the lake .
<u>Step-by-step explanation:</u>
Here we have , A scientist estimates that there are 2.2×107 walleye in Lake Erie. The total ‘volume of Lake Erie is 4.83×1011 cubic meters. A pool with a volume of 200,000 cubic meter is built to model the lake. We need to find How many walleye should be put into the pool to model the conditions in the lake . Let's find out:
In 4.83×1011 cubic meters , there are 2.2×107 walleye . So , in 1 cubic meters :
⇒ ![\frac{2.2(10^7)}{4.83(10^{11})}](https://tex.z-dn.net/?f=%5Cfrac%7B2.2%2810%5E7%29%7D%7B4.83%2810%5E%7B11%7D%29%7D)
According to question we need to find , Number of walleye should be put into the pool of volume 200,000 cubic meter :
⇒ ![\frac{2.2(10^7)}{4.83(10^{11})}(200000)](https://tex.z-dn.net/?f=%5Cfrac%7B2.2%2810%5E7%29%7D%7B4.83%2810%5E%7B11%7D%29%7D%28200000%29)
⇒ ![\frac{2.2(2)(10^{(7+5)})}{4.83(10^{11})}](https://tex.z-dn.net/?f=%5Cfrac%7B2.2%282%29%2810%5E%7B%287%2B5%29%7D%29%7D%7B4.83%2810%5E%7B11%7D%29%7D)
⇒ ![\frac{4.4)(10^{(12-11)})}{4.83}](https://tex.z-dn.net/?f=%5Cfrac%7B4.4%29%2810%5E%7B%2812-11%29%7D%29%7D%7B4.83%7D)
⇒ ![0.91(10)](https://tex.z-dn.net/?f=0.91%2810%29)
⇒ ![9](https://tex.z-dn.net/?f=9)
Therefore , 9 walleye should be put into the pool to model the conditions in the lake .
So Zoe bought 1 pound of potato and 15 pounds of potato magicly appeared? Cause how in the world did she start out with a pound then end up with 16?
We have an equation: 90/? = 120/100
Cross multiply:
120*? = 90*100
⇒ ? = 90*100/120 = 75.
He weighed 75 pounds in fourth grade~
See the attachment hope this helps.
If you multiply two whole numbers you will have a whole number so 3/3 X 4/4 will equal 12/12