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2 years ago

MARKING AS BRAINLIEST! LAST ATTEMPT! ) show ur work

Mathematics

1 answer:

Dvinal [7]2 years ago

3 0

Answer:

√x³=√(x²·x)=x√x

√xy³z=√(x·y²·y·z)=y√xyz

√18x²y=√(3²·2·x²·y)=3x√2y

√32x⁴y²=√(2⁴·2·x⁴·y²)=2²x²y√2=4x²y√2

2√16x⁷y³z⁴=2√(2⁴·x⁶·x·y²·y·z⁴)=2³x³yz²√xy=8x³yz²√xy

-3√180x⁵y=-3√(3²·2²·5·x⁴·x·y)=-3(3)(2)x²√5xy=-18x²√5xy

5√108xyz²=5√(2²·3²·3·x·y·z²)=5(2)(3)z√3xy=30z√3xy

3x√xy¹⁰z⁷=3x√x·y¹⁰·z⁶·z)=3xy⁵z³√xz

x²√x³y²=x²√(x²·x·y²)=x²·x·y√x=x³y√x

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If it takes 16 yards of material to make 5/2 costumes, how much material will be needed to make 19/2 costumes of that same size?

IRISSAK [1]

yards/costumes:16/(5/2) = X/(19/2)

Cross multiply.

(5/2)x = 152

Multiply both sides by 2/5.

x = 101 1/3 yards

7 0

3 years ago

Find the sum of the interior angles of a regular 14-gon.

Ira Lisetskai [31]

9514 1404 393

Answer:

2160°

Step-by-step explanation:

The sum of interior angles of a convex n-gon is ...

angle sum = 180(n -2)°

When n=14, the angle sum is ...

angle sum = 180(14 -2)° = 2160°

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3 years ago

HELP IM FAILING MATH I NEED HELP :(

CaHeK987 [17]

Answer:idk

Step-by-step explanation:

idk

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3 years ago

Read 2 more answers

(3/7 * (- 5/8)) + (1/3 * 5/6) + |- 1/2 - 1/5|

ANEK [815]

Answer:

Exact Form:

1789/2520

Decimal Form:

0.70992063

8 0

2 years ago

The graph of an inverse trigonometric function passes through the point (1, pi/2). Which of the following could be the equation

rodikova [14]

Answer: C) $y=sin^-1 x$

Step-by-step explanation:

Since, the graph of an inverse trigonometric function will pass through the point $(1,\frac{\pi}{2})$ ,

If this point satisfies the function,

For the function $y=cos^{-1} x$

If x = 1

$y=cos^{-1}1=0$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=cos^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=cot^{-1}x$

If x = 1

$y=cot^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cot^{-1}x$ ,

⇒ The graph of $y=cot^{-1}x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=sin^{-1} x$

If x = 1

$y=sin^{-1}1=\frac{\pi}{2}$

Thus, $(1,\frac{\pi}{2})$ is satisfying function $y=sin^{-1} x$ ,

⇒ The graph of $y=sin^{-1} x$ is passing through the point $(1,\frac{\pi}{2})$ .

For the function $y=tan^{-1}x$

If x = 1

$y=tan^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=tan^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$ .

Hence, Option C is correct.

3 0

3 years ago