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masha68 [24]
3 years ago
11

How state the roots as points when I have x=6 and x=-2

Mathematics
1 answer:
dem82 [27]3 years ago
6 0

I don't really know what you're trying to ask because

x = -2 and x=6 are your roots.

But if you want to convert them back to their equation form,

get the other side of the equation to be 0.

x = 6

x - 6 = 0

x = -2

x + 2 = 0

so your original equation had something like (x+2)(x-6)

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Answer:

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Step-by-step explanation:

<u>Informação recuperada:</u>

(UFRGS) Se 10x = 20y , atribuindo 0,3 para log 2 , então o valor de x/y é

1) Primeiro, passando o 10 para o 2º membro como base do logaritmo:

10x=20y \Rightarrow x=log_{10}20y

2) Aplicando a propriedade do produto de logaritmo:

log(AB)= logA+logB

x=log_{10}20y \Rightarrow x=log(2+10)y\Rightarrow x=(0.3+1)y \Rightarrow x=1.3y

3)  Como quero o quociente divido ambos os lados por y

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