The distance between the boat and the ocean's floor is 19m
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How to get the distance from the ship to the ocean's floor?</h3>
We can see this as a right triangle, where the rope with the anchor is the hypotenuse. So we already know that the hypotenuse measures 30m.
We also know an angle, it measures 39°, and we want to get the opposite cathetus to said angle (the height).
Then we use the relation:
Sin(a) = (opposite cathetus)/(hypotenuse).
Replacing the values that we know, we get:
Sin(39°) = d/30m
sin(39°)*30m = d = 18.9m ≈ 19m
The distance between the boat and the ocean's floor is 19m.
If you want to learn more about right triangles, you can read:
brainly.com/question/2217700
9 ft is the answer because a square has four sides, so 36 divided by 4 is 9
Answer:
We have 40% antifreeze and 70% antifreeze and we need to make 240 liters of 64% antifreeze.
We set up 2 equations where "f" is the 40 % and "s" is the 70%
A) f + s = 240
B) .40f + .70s = (.64 * 240) (or 153.6)
To solve both equations we multiply A) by -.40
A) -.40 f - .40 s = -96.00 then we add this to B)
B) .40f + .70s = 153.60
.30s = 57.6
s = 192
f = 48
48 liters of 40% = 19.20 liters of antifreeze
192 liters of 70% = 134.40 liters of antifreeze
That equals 153.60 liters of antifreeze in a TOTAL liquid amount of 240 liters.
Double Check
153.60 / 240 = 64% antifreeze.
Step-by-step explanation:
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Reflection line of reflection y=2
Not too sure could be rotation maybe