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tino4ka555 [31]
3 years ago
6

PLEASE HELP ME! THE QUESTION IS DOWN BELOW IN THE PICTURE

Mathematics
1 answer:
maria [59]3 years ago
6 0

5 = log(0.9) 0.59045

exponential form:

(0.9)^5 = 0.59045

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Peter says that 3/4 of a pizza is always the same as 6/8 of a pizza.Nadia says that while they are equivalent fractions, 3/4 and
Aleksandr-060686 [28]
Peter is, 3/4 of 12 which is 9 peices put of 12 is the same as 6/8 which is still 9 peices bc you multiply and I still simplify to 9


5 0
3 years ago
Select the correct answer from each drop-down menu.
Elodia [21]

Answer:

The left end approaches to + Infinite being an exponential function, and the right end to 0

Step-by-step explanation:

we have to remember the exponential function, the best way to find the answer is plotting the graph or arranging a table of values.

As you can see in the attached graph the y axis gets closer and closer to 0 as it moves forward in the x axis, and as it moves to the left the y axis starts increasing rapidly.

Also you got to keep in mind the way that functions behave in terms of the sign of its variable. for example the 10 in this equation only makes the curve to get wider, but if you change the sign to minus, the answer would be different.

8 0
3 years ago
Simplify the expression.
raketka [301]
<span>
1/4 n (-24+8m-100p)
= -24n/4 + 8mn/4 - 100np/4
= -6n + 2mn - 25np

answer
</span>A. -6n + 2mn - 25np
5 0
3 years ago
I just need help set up
Vilka [71]

Answer:

Step-by-step explanation:

<em>Set up equations (L= Lisa; M = Maria; A = April; J = Jim)</em>

L = 12M

A = 2J

<em>Substitute x for Maria and 6x for Jim</em>

L = 12x

A = 2(6x) = 12x

<em>So, you get:</em>

Maria = x

Jim = 6x

Lisa = 12x

April = 12x

5 0
4 years ago
3500ca = 1fp
MAXImum [283]

Answer: 1fp = 525 minutes

           35fp = 18,375 minutes

<u>Step-by-step explanation:</u>

Solve this using conversions

\dfrac{30\ minutes}{200\ ca } \times \dfrac{3500\ ca}{1\ fp}= 525\ minutes\ per\ fp

For 35 fp, multiply 35 fp by 525 minutes per 1 fp = 18,375

5 0
3 years ago
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