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weqwewe [10]
3 years ago
14

Guys know the answer to the mcdonalds math challenge

Mathematics
1 answer:
aalyn [17]3 years ago
3 0
What is the McDonald's math challenge
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Whats the answer to that question?
gavmur [86]

Answer:

-0.9090... can be written as \frac{10}{11}.

Explanation:

Any <em>repeating </em>decimal can be written as a fraction by dividing the section of the pattern to be repeated <em>by </em>9's.

We can start by listing out

0.909090... = 9/10 + 0/100 + 9/1000 + 0/10000 + 9/100000 + 0/1000000 + ...

Now. we let this series be equal to x, that is

x = 9/10 + 0/100 + 9/1000 + 0/10000 + 9/100000 + 0/1000000 + ...

Now, we'll multiply both sides by 100 .

100x = 90 + 0 + 9/10 + 0/100 + 9/1000 + 0/10000 + ...

Then, subtract the 1st equation from the second like so:

100x = 90 + 0 + 9/10 + 0/100 + 9/1000 + 0/10000 + 9/100000 + 0/1000000 + ...

-x = - 9/10 - 0/100 - 9/1000 - 0/10000 - 9/100000 - 0/1000000 - ...

And we end up with this:

99x=90

Finally, we divide both sides by 99 in order to isolate x and get the fraction we're looking for.

x=\frac{90}{99}

Which can be reduced and simplified to

x=\frac{10}{11}

Hope this helps!

4 0
3 years ago
A sweater for 36.00 at 7% sales tax
blagie [28]
$36 x 1.07 = $38.52
The cost will be $38.52
Tax on this is $2.52
4 0
3 years ago
Erin spent $15.30 on ingredients for cookies she’s making for the school bake sale. How many cookies must she sell at $0.35 a pi
blondinia [14]

Answer:

she needs to sell at least 44 cookies to make a $0.10 profit

Step-by-step explanation:

to find the answer all you have to do is divide 15.30 by 0.35

4 0
3 years ago
Read 2 more answers
Use the value of the first integral I to evaluate the two given integrals. I = integral^3_0 (x^3 - 4x)dx = 9/4 A. integral^3_0 (
Troyanec [42]

Answer:

A) -9/2

B) 9/4

C) -9/2, same as A)

Step-by-step explanation:

We are given that I=\int_0^3 x^3-4x dx=9/4. We use the properties of integrals to write the new integrals in terms of I.

A) \int_0^3 8x-2x^3 dx=\int_0^3 -2(x^3-4x) dx=-2\int_0^3 x^3-4x dx=-2I=-9/2. We have used that ∫cf dx=c∫f dx.

B) \int_3^0 4x - x^3 dx=-\int_0^3 (4x-x^3) dx=\int_0^3-(4x-x^3) dx=\int_0^3 x^3-4x dx=I=9/4. Here we used that reversing the limits of integration changes the sign of the integral.

C) It's the same integral in A)

4 0
3 years ago
Henry can write 5 pages of
kirill [66]

Answer:

13.28

Step-by-step explanation:

5/3 = 1.66

1.66 x 8 = 13.28

(Please tell me if this is wrong)

5 0
3 years ago
Read 2 more answers
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