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expeople1 [14]
3 years ago
5

List the intercepts of the graph.

Mathematics
2 answers:
katen-ka-za [31]3 years ago
7 0
X intercepts: when y = 0
Points (-pi/2,0) and (pi/2,0)
y intercept: when x = 0
Point (0,3)
The answer is D
Volgvan3 years ago
3 0

Answer:

D

x-intercepts = (-\frac{\pi }{2},0), (\frac{\pi }{2},0)

y-intercept = (0,3)

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Find the area of the parallelagram<br>​
sammy [17]

Answer:

The area of the parallelogram is 117.

Step-by-step explanation:

You do 9x13= area

9x13=  117

3 0
3 years ago
Can anyone solve this triangle?
kirill [66]

Answer:

Step-by-step explanation:

a^2+6^2 = 23^2

a^2 = 23^2 - 6^2

a^2 = 529 - 36

a^2 = 493

a = √493

a = 22,20

7 0
4 years ago
What are two numbers multiplied together to get 15 but add to be 12?
KiRa [710]
So x times y=15
x+y=12
solve
x+y=12
subtract x from both sides
y=12-x
subsitute
xy=15
x(12-x)=15
distribute
12x-x^2=15
subtract (12x-x^2) from both sides
0=x^2-12x+15
use quadratic formula which is
x=\frac{ -b+/- \sqrt{b^{2}-4ac} }{2a}
where you have
0=ax^2+bx+c
so
a=1
b=-12
c=15
subsitute
x=\frac{ -(-12)+/- \sqrt{-12^{2}-4(1)(15)} }{2(1)}
x=\frac{ 12+/- \sqrt{144-60} }{2}
x=\frac{ 12+/- \sqrt{84} }{2}
x=\frac{ 12+/- 2\sqrt{21} }{2}
x=6+/- \sqrt{21}
x=6+ \sqrt{21} or 6- \sqrt{21} or aprox
x=10.5826 or 1.41742
the numbers are 10.5826 and 1.41742






3 0
4 years ago
ANSWER FAST
tester [92]

Answer:

exterior angles 1 and 3 I hope it will help you please follow me

7 0
3 years ago
element X is a radioactive isotope such that every 21 years, its mass decreases by half. Given that the initial mass of a sample
pashok25 [27]

Answer:

The percentage rate of decay per year is of 3.25%.

The function showing the mass of the sample remaining after t is A(t) = 80(0.9675)^t

Step-by-step explanation:

Equation for decay of substance:

The equation that models the amount of a decaying substance after t years is given by:

A(t) = A(0)(1-r)^t

In which A(0) is the initial amount and r is the decay rate, as a decimal.

Every 21 years, its mass decreases by half.

This means that A(21) = 0.5A(0). We use this to find r, the percentage rate of decay per year.

A(t) = A(0)(1-r)^t

0.5A(0) = A(0)(1-r)^{21}

(1-r)^{21} = 0.5

\sqrt[21]{(1-r)^{21}} = \sqrt[21]{0.5}

1 - r = 0.5^{\frac{1}{21}}

1 - r = 0.9675

r = 1 - 0.9675 = 0.0325

The percentage rate of decay per year is of 3.25%.

Given that the initial mass of a sample of Element X is 80 grams.

This means that A(0) = 80

The equation is:

A(t) = A(0)(1-r)^t

A(t) = 80(1-0.0325)^t

A(t) = 80(0.9675)^t

The function showing the mass of the sample remaining after t is A(t) = 80(0.9675)^t

8 0
3 years ago
Read 2 more answers
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