Answer: b) 225 c) 475 d) 325
Step-by-step explanation:
I do not know A I am sorry. For the venn diagram, the circle on the left is hockey, right circle is football, and where they meet is both. The left section (only liking hockey) is 100, right section (only liking football) is 225, and middle section (liking both) is 150. I hope that helps you answer it!
No clue. so sorry. will u answer my question?
Answer:
Step-by-step explanation:
Solution :
Population proportion, P = 77%
Sample size is given by n = 55
Sample proportion =
Null hypothesis
The population proportion of the fatalities of the drivers that are related to alcohol = 77%
%
![$H_0 : P = 0.77$](https://tex.z-dn.net/?f=%24H_0%20%3A%20P%20%3D%200.77%24)
Alternate hypothesis, ![$H_a : P < 0.77$](https://tex.z-dn.net/?f=%24H_a%20%3A%20P%20%3C%200.77%24)
Therefore, the test statistics = ![$\frac{0.61 - 0.77}{\sqrt{\frac{0.7 \times 0.23}{55}}}$](https://tex.z-dn.net/?f=%24%5Cfrac%7B0.61%20-%200.77%7D%7B%5Csqrt%7B%5Cfrac%7B0.7%20%5Ctimes%200.23%7D%7B55%7D%7D%7D%24)
= -3.2
Critical value = -1.64
and the rejection zone : test zone, -1.645
Therefore, we fail rejecting ![$H_0$](https://tex.z-dn.net/?f=%24H_0%24)
p value 0.0582
rejection zone :: p value , 0.01
So we fail to reject ![$H_0$](https://tex.z-dn.net/?f=%24H_0%24)
Thus the data does not indicate the population proportion of the drivers fatalities which are related to the alcohols which is less than 77% in the county of Kit Carson.
P = It is a weekend
Q = I will exercise
If "It is a weekend", then "I will exercise"
But "It is NOT a weekend"
Therefore, "I will NOT exercise"
Using P and Q our statement would look like this,
If P, then Q
But not P
Therefore not Q
Or symbolically like this:
P -> Q
~P
![\therefore](https://tex.z-dn.net/?f=%5Ctherefore)
~Q
I'm sorry that this doesn't match up with the options you posted.
Maybe they didn't paste correctly.